Answer:
<h2> 40in^3</h2>
Step-by-step explanation:
Step one:
given data
dimension of the box
lengh= 5 in
width= 2 in
height =4 in
Required
the volume of the box
the expression for the volume is
V=L*W*H
V=5*2*4
V=40 in^3
Hence the volume of sand the box can take is 40in^3
Answer:
hi.
Step-by-step explanation:
download photo math
Given:
Monthly fees for the local pool are $8 per month and $2 per visit.
Hector pays $34 in pool fees total for the month.
To find:
The number of times he visit the pool.
Solution:
We have,
Monthly fee of pool = $8
Additional fee = $2 per visit
Let Hector visit x times.
Additional fee for x times = $2x
Total fee = Monthly fee + Additional fee
![34=8+2x](https://tex.z-dn.net/?f=34%3D8%2B2x)
![34-8=2x](https://tex.z-dn.net/?f=34-8%3D2x)
![26=2x](https://tex.z-dn.net/?f=26%3D2x)
Divide both sides by 2.
![\dfrac{26}{2}=x](https://tex.z-dn.net/?f=%5Cdfrac%7B26%7D%7B2%7D%3Dx)
![13=x](https://tex.z-dn.net/?f=13%3Dx)
Therefore, Hector visit the pool 13 times.
C(a,b), because the x-coordinate( first coordinate) is a (seeing as it is situated directly above point B, which also has an x-coordinate of a) and the y-coordinate ( second coordinate) is b (seeing as it is situated on the same horizontal level as point D, which also has a y-coordinate of b)
the length of AC can be calculated with the theorem of Pythagoras:
length AB = a - 0 = a
length BC = b - 0 = b
seeing as the length of AC is the longest, it can be calculated by the following formula:
It is called "Pythagoras' Theorem" and can be written in one short equation:
a^2 + b^2 = c^2 (^ means to the power of by the way)
in this case, A and B are lengths AB and BC, so lenght AC can be calculated as the following:
a^2 + b^2 = (length AC)^2
length AC = √(a^2 + b^2)
Extra information: Seeing as the shape of the drawn lines is a rectangle, lines AC and BD have to be the same length, so BD is also √(a^2 + b^2). But that is also stated in the assignment!