<span> (x + 3) • (x - 12)
</span>
The first term is, <span> <span>x2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> -9x </span> its coefficient is <span> -9 </span>.
The last term, "the constant", is <span> -36 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -36 = -36</span>
Step-2 : Find two factors of -36 whose sum equals the coefficient of the middle term, which is <span> -9 </span>.
<span><span> -36 + 1 = -35</span><span> -18 + 2 = -16</span><span> -12 + 3 = -9 That's it</span></span>
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -12 and 3
<span>x2 - 12x</span> + 3x - 36
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-12)
Add up the last 2 terms, pulling out common factors :
3 • (x-12)
Step-5 : Add up the four terms of step 4 :
(x+3) • (x-12)
Which is the desired factorization
Final result :<span> (x + 3) • (x - 12)</span>
Supplementary angles need to equal 180 degrees
one angle = t
the other angle = 4 x t or 4t
so we now have t + 4t = 180
4 + 4t = 5t
so we have 5t = 180
divide both sides by 5:
t = 180 /5
t = 36
so angle t = 36 degrees
the other angle = 4 x 36 = 144 degrees
Answer:
Step-by-step explanation:
Answer:
Mean = 3.7
Variance = 2.61
Step-by-step explanation:
From the data given; we can represent our table into table format for easier solution and better understanding.
Given that:
A highway engineer knows that his crew can lay 5 miles of highway on a clear day, 2 miles on a rainy day, and only 1 mile on a snowy day
Let X represent the crew;
P(X) represent their respective probabilities
clear day rainy day snowy day
X 5 2 1
P(X) 0.6 0.3 0.1
From Above; we can determine our X*P(X) and X²P(X)
Let have the two additional columns to table ; we have
X P(X) X*P(X) X²P(X)
5 0.6 3 15
2 0.3 0.6 1.2
1 0.1 0.1 0.1
Total 1.0 3.7 16.3
The mean 
can be calculated by using the formula:
Therefore ; mean = 3.7
Variance 
Variance = 16.3 -3.7²
Variance = 16.3 - 13.69
Variance = 2.61
The ordered pair which makes both inequalities true is (-2, 2).
It is given that inequalities are
y < -x + 1 and y > x
For y < -x + 1
Substituting every ordered pair,
1) (-3, 5)
⇒ 5 < - (-3) + 1
⇒ 5 < 3 + 1
⇒ 5 < 4 is false
2) (-2, 2)
⇒ 2 < -(-2) + 1
⇒ 2 < 2 + 1
⇒ 2 < 3 is true
3) (-1, -3)
⇒ -3 < - (-1) + 1
⇒ -3 < 1 + 1
⇒ -3 < 2 is true
4) (0, -1)
⇒ -1 < -0 + 1
⇒ -1 < 1 is true
Now , for y > x
1) (-3, 5)
⇒ 5 > -3 is true
2) (-2, 2)
⇒ 2 > -2 is true
3) (-1, -3)
⇒ -3 > -1 is false
4) (0, -1)
⇒ -1 > 0 is false
Therefore ,the ordered pair which makes both inequalities true is (-2, 2).
To know more about Inequalities here
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