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3 years ago

Question 30 of 44 Need help ASAP

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

3 0

Answer:

Sorry but where r the questions

Step-by-step explanation:

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Which of the following functions is graphed below?

mrs_skeptik [129]

Step-by-step explanation:

For y = x^3 - 4 when x = 0, y = -4.

For y = x^2 + 3 when x = 0, y = 3.

Looking at the graph, the y-intercept of the function is below 0. Hence the bottom part is from x^3 - 4 and the top is from x^2 + 3.

The bottom part has a dark circle, which means when x = 1 it belongs to x^3 - 4.

Hence the answer is D.

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Which is a factor of each term of the polynomial?<br><br> (3d2 – 10d)

nydimaria [60]

Answer:

d(3d-10)

Step-by-step explanation:

You pull out the common factor of d from both terms, and group the remaining terms inside a parenthesis.

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What is the inequality shown in the graph

rodikova [14]

It must be ≤ instead of ≥.

y ≤ - 3·x + 4

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Co-payment is 20% of $23,890 , her co-payment is

Sidana [21]

the answer to the question is 4,778

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3 years ago

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

4 years ago