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Tems11 [23]
3 years ago
9

I will give you BRAINLIEST for the correct answer

Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0

Wouldnt B be correct

Step-by-step explanation:

There are nine teas sold for every five sodas so 9:5

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Maria solved the equation. <br><br> What methods did she use and in what order did she use them?
Brilliant_brown [7]

1 ⇒ 2 : eliminate parentheses using the distributive property

2 ⇒ 3 : combine like terms

3 ⇒ 4 : add 36 using the addition property of equality

4 ⇒ 5 : divide by 12 using the division property of equality

6 0
3 years ago
Read 2 more answers
Solve each system of equations using substitution. Show all work.
Crank
First make an equaiton equal to only 1 variable 1. x-y=2 add y to both sides x=y+2 sub 4(y+2)-3y=11 4y+8-3y=11 y+8=11 y=3 sub x=y+2 x=3+2 x=5 (5,3) 2. x+2y=7 subtract 2y x=7-2y sub -2(7-2y)+3y=14 -14+4y+3y=14 7y-14=14 7y=28 y=4 sub x=7-2y x=7-2(4) x=7-8 x=-1 (-1,4) 3. 6x-y=-4 subtract 6x -y=-4-6x multily -1 y=4+6x sub 2x+2(4+6x)=15 2x+8+12x=15 14x+8=15 14x=7 x=1/2 sub y=4+6x y=4+6(1/2) y=4+3 y=7 (1/2,7) 1. (5,3) 2. (-1,4) 3. (1/2,7)
7 0
4 years ago
A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions
salantis [7]

Dimensions are length 20 meter and width 14 meter

<em><u>Solution:</u></em>

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

<em><u>A rectangle has width that is 6 meters less than the length</u></em>

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

<em><u>The area of the rectangle is given by formula:</u></em>

Area = length \times width

<em><u>Substituting the values we get,</u></em>

Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0

<em><u>Solve the above equation by quadratic formula</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}

a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14

Since, length cannot be negative, ignore a = -14

<em><u>Thus solution of length is a = 20</u></em>

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0
4 years ago
Solve: x^4 + 2x^3 - x^2 - 4^x - 2 = 0.​
natta225 [31]

By defferentiating the about using product rule

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7 0
3 years ago
25^2-3x = 1/5^4<br> solve for x show all steps<br> HELP ME PLEASEEE;(
fgiga [73]
If its (1/5)^4
625-3x=625
-3x=0
x=0

If its 1/5^4 then the answer is 390624/1975
I'm betting its (1/5)^4

Order of operations matters
5 0
4 years ago
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