Answer: b. 8.56 to 21.44
Step-by-step explanation:
Let 
be the mean number of pushups that can be done.
As per given , we have
Sample size : n= 10
Degree of freedom = n-1=9
Sample mean : 
Sample standard deviation : 
Significance level : α=1-0.95=0.05
From t- distribution table ,
Critical two -tailed t-value for α=0.05 and df = 9 is
Confidence interval for is given by :-
Hence, the 95% confidence interval for the true mean number of pushups that can be done is 8.56 to 21.44.
Answer:
yes because it is in the positive side
So what your saying is that James can type 5 words and Anne can type 8 words right? And James types 150 so how many can Anne type? Is that what your asking?
Divide 2/3 by 3/64 and you will get the number of cups of punch. It doesn't come out evenly, but that's the way to do this.there is a total of 2/3 gallon of punch. Each guests has a cup of 3/64 gallon of punch. Now many 3/64 gallon of punch can you fit in 2/3 gallon of punch, that will tell you how many guests there are. so naturally we want to divide<span> ( 2/3 ) / ( 3/64).</span>
Given:
6 male professores
9 female professores
5 male teaching assistants
6 female teaching assistants
Sol:.
N (professors)
N(Male)
N(professors and male)
N(professors OR male) = N(professors) + N(males) -N(professor OR male)
N(People to choose from)
Then probablitiy is:
Then the probability is 10/13
