Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then ...
Let 2n + 5 = the second and larger number.
Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
n + (2n + 5) = 26
n + 2n + 5 = 26
Collecting like-terms on the left, we get:
3n + 5 = 26
3n + 5 - 5 = 26 - 5
3n + 0 = 21
3n = 21
(3n)/3 = 21/3
(3/3)n = 21/3
(1)n = 7
n = 7
Therefore, ...
2n + 5 = 2(7) + 5
= 14 + 5
= 19
CHECK:
n + (2n + 5) = 26
7 + (19) = 26
7 + 19 = 26
26 = 26
Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.
Hope this helps :)
The remainder theorem tells you that when you do synthetic division with the 6, the remainder will be the same value as when you evaluate the function with the value of 6.
The answer is 15
Answer:
a. 4(d+3e)
b. 6(3x+5y)
c. 7(3a+4y)
d. 8(3f+7g)
Step-by-step explanation:
In each case we find the greatest common factor of the numbers. That is the greatest number that goes into both the numbers. Then we factor it out in front and inside parentheses we divide each original term by the greatest common factor:
a. 4d+12e, GCF: 4
b. 18x+30y, GCF: 6
c. 21a+28y, GCF: 7
d. 24f+56g, GCF: 8
10+2h because 10 dollars is coming whether you like it or not then you have to pay 2 dollars per each hour you use it....i would just carry the kid.
Answer:
a=-4, b=-4. (-4, -4).
Step-by-step explanation:
-3a+7b=-16
-9a+5b=16
-------------------
-3(-3a+7b)=-3(-16)
-9a+5b=16
---------------------------
9a-21b=48
-9a+5b=16
------------------
-16b=64
b=64/-16
b=-4
-3a+7(-4)=-16
-3a-28=-16
-3a=-16+28
-3a=12
a=12/-3
a=-4
