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4 years ago

How do you factor 35x^2+26-16? Show work please.

Mathematics

1 answer:

Sedbober [7]4 years ago

3 0

well, first off, we do a quick prime factoring of the leading term's coefficient, 35, and the constant, 16.

35 = 5*7

16 = 2*2*2*2

and the rest is just a mix and match.

what combination from the factors of 35 and the factors of 16, can provide a product whose sum is the middle term 26? well, without further adieu.

we can try 5*2*2 + 7*2*2, and that's 20 and 28, ok, 28 - 20 is 8, so that won't work.

another can be 5*2*7 and 2*2, that's 70 and 4, 70 - 4 is 56, that won't work either.

5*2*2*2 and 7*2, that's 40 and 14, hmmm 40 - 14 = 26!!! holly guacamole!

so then,

$\bf 35x^2+26x-16\implies (5x-\stackrel{\stackrel{2}{\downarrow }}{2})(7x+\stackrel{\stackrel{2\cdot 2\cdot 2}{\downarrow }}{8})$

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3 years ago

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3 years ago

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tino4ka555 [31]

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Step-by-step explanation:

A recursive rule is a formula that in which each term is expressed as a function of its preceding term(s), meaning in order to get to the nth term you have to express it in a form of the term that comes before it. In our case the a(n-1) term

So for the sequence -9, -2, 5, 12

The nth term is any number on the sequence and

-2 is the a(n-1) term for -9

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3 years ago

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In the given question,

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To prove the formula we take the left side terms to the right side terms

The left side is sin 3A+sin A.

As we know that sin 3A = 3sinA − 4sin^3A

To solve the left side we put the value of sin 3A in sin 3A+sin A.

=sin 3A+sin A

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Simplifying

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Taking 4sinA common from both terms

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To learn more about formula of trigonometry terms link is here

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2 years ago

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