1. Using your straightedge, draw a reference line, if one is not provided.
2. Copy the side of the square onto the reference line, starting at a point labeled A'.
3. Construct a perpendicular at point B' to the line through ab2.
4. Place your compass point at B', and copy the side of the square onto the perpendicular b'g. Label the end of the segment copy as point C.
5. With your compass still set at a span representing AB, place the compass point at C and swing an arc to the left.
6. Holding this same span, place the compass point at A' and swing an arc intersecting with the previous arc. Label the point of intersection as D.
7. Connect points A' to D, D to C, and C to B' to form a square.
Answer:9
Step-by-step explanation:
Answer: -1
Step-by-step explanation:
Given: The set of points W(4, 4), X(6, 2), Y(-8, 16) are collinear
The slope of a line passing through points (a,b) and (c,d) is given by :-
Now, the slope of line passing through W(4, 4), X(6, 2) is given by :-
Hence, the slope of line passing through W(4, 4), X(6, 2), Y(-8, 16) =-1
<h2>SOLVING</h2>
How do the graphs f(x) and f^-1(x) relate?
These two functions are inverses of each other.
That's the way these two are related to each other.
f^-1(x) is the inverse function of f(x), and f(x) is the inverse function of f^-1(x).