The prime numbers between 20 and 30 are: 23, 29
So there are 2 prime numbers this time, instead of 4.
So this proves that there aren't the same number of prime numbers between 2 consecutive multiples of 10.
A^2+b^2=c^2
(10.1)^2+(12.2)^2=c^2
102.01+148.84=c^2
250.85=c^2
15.8=c
Hypotenuse is approx 15.8 inches
Answer:
Step-by-step explanation:
MX = XN
5r² + 2r + 52 = 4r² + 12r + 27
5r² - 4r² + 2r - 12r + 52 - 27 = 0
r² - 10r + 25 = 0
(r - 5)² = 0
r - 5 = 0
r = 5
4r² + 12r + 27
4•5² + 12•5 + 27
4•25 + 60 + 27
100 + 60 + 27
187
The Second one
I hope I helped you.
Answer:
100cm
Step-by-step explanation:
The tenths of a cm are 10, 20, 30, 40 etc..
