4x^2-400=0 square roots and solving quadratics

What is the distance between (2, -1) and (-1, -5) on the coordinate plane? 7 units 6 units 5 units 4 units

morpeh [17]

You can use the distance formula:
 $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Plug in the given coordinates:
 $\sqrt{(-5-2)^2 + (-1+1)^2}$

$\sqrt{(7)^2 + (0)^2}$

$\sqrt{49+0}$

$\sqrt{49}=7$

Final answer : 7units

3 0

3 years ago

Write an equivalent expression for -(3b+2)+4

Lerok [7]

Answer:

-3b+2

Step-by-step explanation:

-3b-2+4

-3b+2

4 0

3 years ago

Solve this problem PLS SOLVE ASAP!!

guajiro [1.7K]

α $a^{2} (-4+6)$

8 0

3 years ago

There were 2430 Major League Baseball games played in 2009, and the home team won the game in 53% of the games. If we consider t

Ivahew [28]

Answer:

$z=\frac{0.53 -0.5}{\sqrt{\frac{0.5(1-0.5)}{2430}}}=2.958$

$p_v =P(Z>2.958)=0.0015$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion is significantly higher than 0.5 .

Step-by-step explanation:

1) Data given and notation

n=2430 represent the random sample taken

$\hat p=0.53$ estimated proportion when the home team won the game

$p_o=0.5$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is higher than 0.5 or 50%:

Null hypothesis: $p\leq 0.5$

Alternative hypothesis: $p > 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.53 -0.5}{\sqrt{\frac{0.5(1-0.5)}{2430}}}=2.958$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>2.958)=0.0015$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion is significantly higher than 0.5 .

8 0

3 years ago

Use the quadratic formula to solve 2x^2=5x+6. Leave your answer in radical form. Show all of your work!

Westkost [7]

Answer:

In radical from 169/50 , 177/200

Step-by-step explanation:

Given:

$2x^2=5x+6\\\\2x^2-5x-6=0\\\\Where, a=2 , b=-5 , c=-6$

Find:

Value of $x$

Computation:

Using quadratic formula:

$\frac{-b\±\sqrt{b^2-4ac} }{2a}\\\\By\ putting\ all\ value\\\\ \frac{-(-5)\±\sqrt{(-5)^2-4(2)(-6)} }{2(2)}\\\\ \frac{5\±\sqrt{25+48} }{4}\\\\ \frac{5\±8.54 }{4}\\\\\frac{5+8.54 }{4},\frac{5-8.54 }{4} \\\\3.38 , 0.885$

Value of $x$ 3.38 , 0.885

In radical from 169/50 , 177/200

8 0

3 years ago