Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8
Answer:
A) only figure 1 and figure 2
Step-by-step explanation:
Answer:
Step-by-step explanation:
Find the area under the standard normal curve between z = 1 and z = 2.
- <em>13.59% or 0.1359</em>
- <em>THANXXX</em>
- <em>HEYAAA</em>
Not really sure how to answer this hope someone helps you!
The correct congruence statement for the triangles shown is∆ BLG~=∆PFX.
