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gregori [183]
3 years ago
12

Chris is a project manager. He would like to schedule a status meeting for the next week. Several of the group members work at a

nother site. What should Chris do? create a business process flow brainstorm ideas with the team use instant messaging to set up a meeting set up a meeting and conference call and send the phone number and pass code to the attendees
Computers and Technology
1 answer:
lesya [120]3 years ago
4 0

Answer:

chris needs a new job so we don't have to stress about these answers anymore.

Explanation:

baby u light up my world like nobody else the way that u flip ur hair

You might be interested in
Why would an information systems security practitioner want to see network traffic on both internal and external network traffic
Pepsi [2]

Answer:

To see who is accessing data and also where it is going

Explanation:

An information systems practitioner is a person who is involved in the planning and and also implementation of IT resources for any organization which he at she works.

The information systems practitioner would want to want to see network traffic on both internal and external network traffic so as to know who is accessing data and to also know where it is going.

8 0
3 years ago
The compare_strings function is supposed to compare just the alphanumeric content of two strings, ignoring upper vs lower case a
Korolek [52]

Answer:

There is a problem in the given code in the following statement:

Problem:

punctuation = r"[.?!,;:-']"

This produces the following error:

Error:

bad character range

Fix:

The hyphen - should be placed at the start or end of punctuation characters. Here the role of hyphen is to determine the range of characters. Another way is to escape the hyphen - using using backslash \ symbol.

So the above statement becomes:

punctuation = r"[-.?!,;:']"  

You can also do this:

punctuation = r"[.?!,;:'-]"  

You can also change this statement as:

punctuation = r"[.?!,;:\-']"

Explanation:

The complete program is as follows. I have added a print statement print('string1:',string1,'\nstring2:',string2) that prints the string1 and string2 followed by return string1 == string2  which either returns true or false. However you can omit this print('string1:',string1,'\nstring2:',string2) statement and the output will just display either true or false

import re  #to use regular expressions

def compare_strings(string1, string2):  #function compare_strings that takes two strings as argument and compares them

   string1 = string1.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   string2 = string2.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   punctuation = r"[-.?!,;:']"  #regular expression for punctuation characters

   string1 = re.sub(punctuation, r"", string1)  # specifies RE pattern i.e. punctuation in the 1st argument, new string r in 2nd argument, and a string to be handle i.e. string1 in the 3rd argument

   string2 = re.sub(punctuation, r"", string2)  # same as above statement but works on string2 as 3rd argument

   print('string1:',string1,'\nstring2:',string2)  #prints both the strings separated with a new line

   return string1 == string2  # compares strings and returns true if they matched else false

#function calls to test the working of the above function compare_strings

print(compare_strings("Have a Great Day!","Have a great day?")) # True

print(compare_strings("It's raining again.","its raining, again")) # True

print(compare_strings("Learn to count: 1, 2, 3.","Learn to count: one, two, three.")) # False

print(compare_strings("They found some body.","They found somebody.")) # False

The screenshot of the program along with its output is attached.

4 0
4 years ago
Suppose we are given an arbitrary digraph G = (V, E) that may or may not be a DAG. Modify the topological ordering algorithm so
lianna [129]

Answer:

Check the explanation

Explanation:

We can utilize the above algorithm with a little in modification. If in each of the iteration, we discover a node with no inward edges, then we we’re expected succeed in creating a topological ordering.

If in a number of iteration, it becomes apparent that each of the node has a minimum of one inward edge, then there must be a presence of cycle in the graph.

So our algorithm in finding the cycle is this: continually follow an edge into the node we’re presently at (which is by choosing the first one on the adjacency list of inward edges to decrease the running time).

Since the entire node has an inward edge, we can do this continually or constantly until we revisit a node v for the first time.

The set of nodes that we will come across among these two successive visits is a cycle (which is traversed in the reverse direction).

3 0
4 years ago
Which is a good plan for backing up data?
IgorC [24]
A good plan for backing up data is to setup an automatic backup to an external drive or cloud based storage on a regular basis.
6 0
4 years ago
For each of the descriptions below, perform the following tasks:
ss7ja [257]

ANSWER:

1)i. The relationship is a degree of 2 ( i.e Binary). The cardinality of the relationship is One-to-Many.

ii. The model is from piano description to piano manufacturer.

PIANO:

Model name

Model number

Serial number

Manufacturing completion date

MANUFACTURER:

Ebony and Ivory

2)i. The relationship is a degree of 2 ( i.e Binary). The cardinality of the relationship is Many-to-Many.

ii. The model is from piano description to Technician.

PIANO:

Model name

Model number

Serial number

Manufacturing completion date

TECHNICIAN

Employee number

Specialty

3)i. The relationship is a degree of 2 (i.e Binary). The cardinality of the relationship is Many-to-One.

ii. The model is from Technician to Technician

TECHNICIAN:

Lower rank

TECHNICIAN:

Higher rank

5 0
3 years ago
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