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il63 [147K]
3 years ago
9

When you use the Bing Image Search for online pictures, you will be searching the Internet for pictures that have been filtered

based on the _____________ licensing system.
Computers and Technology
2 answers:
just olya [345]3 years ago
7 0

Answer:

Creative commons licensing system

Explanation:

If you use the Bing image search you will be searching the Internet for pictures that have been filtered based on the creative Commons licensing system meaning you will have to search the internet for picture that have licence that will give you the right to have the pictures because the owner has given you the licence to share or use the picture he created

Therefore Commons licenses is the licenses to get permission to do any of the things with a work that the law reserves exclusively to a licensor and that the license does not expressly allow.

marshall27 [118]3 years ago
7 0

Answer:

Creative commons

Explanation:

Bing is a web browser search engine used to promote easy navigation on the internet. It provides related results based on the inputted values in the browser. It also accepts pictures or image values for it's search.

The creative commons licensing system facilitate or allows for creators of products to grant users free acquisition, use and modification of products. It is also known as "CC".

With this, a picture can be searched in the Bing image search engine, downloaded and modified without risk of violation.

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Explanation:

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3 years ago
Write a simple Html structure and explain the meaning of each line
seropon [69]

Answer:

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3 years ago
Illustrate that the system is in a safe state by demonstrating an order in which the threads may complete.If a request from thre
Kamila [148]

Answer:

a. safe sequence is T2 , T3, T0, T1, T4.

b. As request(T4) = Available, so the request can be granted immediately

c. As request(T2) < Available, so the request can be granted immediately

d. As request(T3) < Available, so the request can be granted immediately.

Explanation:

It will require matrix

[i, j] = Max [i, j] – Allocation [i, j]

A B C D

T0 3 3 3 2

T1 2 1 3 0

T2 0 1 2 0

T3 2 2 2 2

T4 3 4 5 4

Available = (2 2 2 4)

1. Need(T2) < Available so, T2 can take all resources

Available = (2 2 2 4) + (2 4 1 3) (Allocation of T2) = (4 6 3 7)

2. Need(T3)<Available so, T3 will go next

Available = (4 6 3 7) + (4 1 1 0) = (8 7 4 7)

Like wise next T0, T1, T4 will get resources.

So safe sequence is T2 , T3, T0, T1, T4.

(Note, there may be more than one safe sequence).

Solution b.

Request from T4 is (2 2 2 4) and Available is (2 2 2 4)

As request(T4) = Available, so the request can be granted immediately.

Solution c.

Request from T2 is (0 1 1 0) and Available is (2 2 2 4)

As request(T2) < Available, so the request can be granted immediately.

Solution d.

Request from T3 is (2 2 1 2) and Available is (2 2 2 4)

As request(T3) < Available, so the request can be granted immediately.

5 0
3 years ago
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