They have a chance of being blocked
Answer:
see explaination for program code
Explanation:
scalar_product = 0
li=[]
li2=[]
#reading numbers1.txt and numbers2.txt intoli and li2 respectively
with open('numbers1.txt') as n1, open('numbers2.txt') as n2:
for line1 in n1:
li.append(int(line1))
for line2 in n2:
li2.append(int(line2))
#storing min list size into variable l
a=len(li)
b=len(li2)
if a<b:
l=a
else:
l=b
#calculating scalar product
for i in range(l):
scalar_product=scalar_product+li[i]*li2[i]
print("scalar product is",scalar_product)
Answer:
- <u>1,000W</u> (rounded to one significant figure)
Explanation:
I will answer in English.
The question is:
- <em>What is the power of a filament lamp that connects to the 220 V network, knowing that it has a resistance of 50 ohms?</em>
<em />
<h2>Solution</h2>
<em />
<em>Power</em>, <em>voltage</em>, <em>resistance</em>, and current, are related by either of the following equations:
Where:
- R is resistance in ohms (Ω)
- V is voltage in volts (V), and
- I is current in amperes (A)
Since you know the voltage (<em>220V</em>) and the resistance (<em>50Ω</em>), you can use the last equation:
Since the magnitude 50Ω has one significant figure, your answer should be rounded to one significant figure. That is <u>1,000W.</u>
A computational instruction with operands is command so computational instructionis just a opcode.
B. opcode
