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pantera1 [17]
3 years ago
15

A circular copper disk of diameter D=10 cm rotates at frequency =1800 rev/min about an axis through its center and at right angl

es to the disk. A uniform magnetic field B of 10,000 gauss is perpendicular to the disk. What potential difference e develops between the axis of the disk and its rim? Express your answers in terms of variables first and then plug in numbers afterword
Computers and Technology
1 answer:
MAXImum [283]3 years ago
7 0

Answer:

Induced current is 0.226 A

Explanation:

To calculate potential difference we have

E =1/2Bomega*r2 =1/2*1*1800*3.14*0.05=141.3

putting values we get

the p.d is 141.3

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Answer: See explanation

Explanation:

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What is output? public class MathRecursive { public static void myMathFunction(int a, int r, int counter) { int val; val = a*r;
ycow [4]

Answer:

The output of the program is:

2 4 8 16 32 64 End

Explanation:

See attachment for proper presentation of the program

The program uses recursion to determine its operations and outputs.

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Its operation goes thus:

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if (counter > 4) { System.out.print("End"); } : Not true

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else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 8; r = 2; counter = 3

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else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

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a= 32; r = 2; counter = 5

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if (counter > 4) { System.out.print("End"); } : True

<em>This prints "End"</em>

So; the output of the program is:

2 4 8 16 32 64 End

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