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Minchanka [31]
3 years ago
12

CHALLENGE ACTIVITY |

Computers and Technology
1 answer:
fredd [130]3 years ago
6 0

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

  double maxVal = 0.0;    

  if (num1 > num2) { // if num1 is greater than num2,

     maxVal = num1;  // then num1 is the maxVal.    }

  else {          

     maxVal = num2;  // num2 is the maxVal.   }

  return maxVal; }  

int main() {

  double numA;

  double numB;

  double numY;

  double numZ;

  double maxSum = 0.0;  

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

  cout << "maxSum is: " << maxSum << endl;   }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement  FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0  as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

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Given two Strings String s1 = "11223351638791377189728193"; String s2 = "983763978669976862724569282405742578"; and String varia
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Answer:

import java.math.BigInteger;  

public class Main {  

public static void main(String[] args)  {  

String s1 = "11223351638791377189728193";   String s2 = "983763978669976862724569282405742578";

BigInteger num1 = new BigInteger(s1);  

BigInteger num2 = new BigInteger(s2);  

BigInteger product = num1.multiply(num2);  

String s3 = product.toString(10);

System.out.println(s3);  

}  

}  

Explanation:

Because s1 and s2 contain large integers, the program need the biginteger module in other to compute the products of s1 and s2 when converted to integers.

This line initializes the two string variables s1 and s2

String s1 = "11223351638791377189728193";   String s2 = "983763978669976862724569282405742578";

The next two lines convert the two strings to BigInteger. This allows the program to multiply large integers

<em> BigInteger a = new BigInteger(s1);   </em>

<em>BigInteger b = new BigInteger(s2);  </em>

<em />

This computes the product of the two big integers

BigInteger product = num1.multiply(num2);  

This converts the product to String s3

String s3 = product.toString(10);

This prints s3

System.out.println(s3);  

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Answer:

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             return 1;

      }

      return number + sum(number -1);

}

Explanation:

This is a recursive function, it means that is a function that calls itself for example: if you call the function with sum(5) the process is :

sum(5)

   |______ 5 + sum(4)

                           |_______ 4 + sum(3)

                                                       |______ 3 + sum(2)

                                                                                   |_____2 + sum(1)

                                                                                                        |_____ 1

                                                                                                 

the result is 1+2+3+4+5 = 15

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