To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership. So set the no-membership cost equal to the yearly membership cost and solve.
no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day. So if we let d = number of days, our cost can be calculated by "7d"
a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"
Set them equal to each other and solve:
7d = 200 + 3d
4d = 200
d = 50
So you would need to attend the classes for at least 50 days to justify a yearly membership. I hope that helps!
Consecutive odd integers are 2 apart
they are
n,n+2,n+4
3(n²)=12+(n+2)(n+4)
expand
3n²=12+n²+6n+8
3n²=n²+6n+20
minus n² both sides
2n²=6n+20
divide bot sides by 2
n²=3n+10
minus 3n+10 both sides
n²-3n-10=0
factor
(n-5)(n+2)=0
n-5=0
n=5
n+2=0
n=-2
has to be odd, so no
n=5
n+2=7
n+4=9
the integers are 5,7,9
Answer:
x=sqrt(3)/2 or -sqrt(3)/2
Step-by-step explanation:
(x,1/2) is on the unit circle at pi/6 and 5pi/6.
so x is either sqrt(3)/2 or -sqrt(3)/2
Answer:
B?
Step-by-step explanation:
