Question

Using the properties of exponents and logarithms, find the value of x in 19+2 in x=25

Answer 1

Answer:

x = e³

Step-by-step explanation:

Using the property of logarithms

• $log_{b}$ x = n ⇔ x = $b^{n}$

Given

19 + 2lnx = 25 ( subtract 19 from both sides )

2lnx = 6 ( divide both sides by 2 )

lnx = 3 [ note lnx = $log_{e}$ x ]

x = e³