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3 years ago

Please help thank u!!!!!

Computers and Technology

2 answers:

Damm [24]3 years ago

4 0

Answer:

i believe you can change slides with the arrow keys not entirely sure though

Explanation:

iragen [17]3 years ago

3 0

Answer:

using the arrows

pressing space

and clicking the mouse

Explanation:

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A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

how many usable host addresses are available for each subnet when 4 bits are borrowed from a class C IP address

jonny [76]

Answer:

The answer is "14".

Explanation:

Let the IP address $= 196.45.204.0$

When it borrowed 4 bits

$\therefore\\\\ subnet = 28$

$IP= \frac{196.45.204.0}{28}\\\\ 28 \to 11111111.11111111.11111111.11110000$

If the borrowed bits are left out then:

The Number of useable host addresses:

$= {(2^4) - 2} \\\\ = 16-2\\\\ =14$

3 0

3 years ago

What is digital museum

umka2103 [35]

Access hundreds of professional development resources for museum professionals. Museum professionals can benefit at any career stage from student to retiree. Student Membership. Industry Membership. Established Since 1906. Museum Memebership. 501(c)3 Nonprofit Org.

7 0

3 years ago

Read 2 more answers

Lera25 [3.4K]

Answer:

The answer to this question can be given as:

Method:

public static void showTwos(int number) //method definition.

{

method body.

System.out.print(number + " = "); //print number

while (number % 2 == 0) //condition

{

System.out.print("2 * "); //print message.

number = number / 2;

}

System.out.println(number); //print value.

}

Explanation:

In the above method definition firstly, we declare the method showTwos() that name is already given in the question then we pass a variable number as a parameter in the method. In this first, we take input number from the user and pass into this method. In this method we use a while loop it is an entry control loop in this loop first we modules the number if it is equal to 0.Then we divide the number by 2 and in the last, we print the value.

4 0

3 years ago

______ refers to the physical or logical arrangement of a network.

yarga [219]

Topology refers to the physical or logical arrangement of a network.

3 0

3 years ago