Answer:
A) Number of bits for byte = 6 bits
B) number of bits for index = 17 bits
C) number of bits for tag = 15 bits
Explanation:
Given data :
cache size = 64 kB
block size = 32 -byte
block address = 32 -bit
number of blocks in cache memory
cache size / block size = 64 kb / 32 b = 2^11 hence the number of blocks in cache memory = 11 bits = block offset
A) Number of bits for byte
= 6 bits
B) number of bits for index
block offset + byte number
= 11 + 6 = 17 bits
c ) number of bits for tag
= 32 - number of bits for index
= 32 - 17 = 15 bits
Answer:
ranforce = randi([0, 12]);
if (ranforce == 0)
disp('There is no wind')
else if(ranforce>0 && ranforce <7)
disp('There is a breeze')
else if(ranforce>6 && ranforce <10)
disp('This is a gale')
else if(ranforce>9 && ranforce <12)
disp('It is a storm')
else if(ranforce==12)
disp('Hello, Hurricane!')
end
Explanation:
<em>Replace all switch case statements with if and else if statements.</em>
<em>An instance is:</em>
<em>case {7,8,9}</em>
<em>is replaced with</em>
<em>else if(ranforce>9 && ranforce <12)</em>
<em>All other disp statements remain unchanged</em>
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