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suter [353]
3 years ago
8

/*

Computers and Technology
1 answer:
Lera25 [3.4K]3 years ago
4 0

Answer:

The answer to this question can be given as:

Method:

public static void showTwos(int number)  //method definition.

{

method body.  

System.out.print(number + " = ");  //print number

while (number % 2 == 0)   //condition

{

System.out.print("2 * ");    //print message.

number = number / 2;

}

System.out.println(number);    //print value.

}

Explanation:

In the above method definition firstly, we declare the method showTwos() that name is already given in the question then we pass a variable number as a parameter in the method. In this first, we take input number from the user and pass into this method. In this method we use a while loop it is an entry control loop in this loop first we modules the number if it is equal to 0.Then we divide the number by 2 and in the last, we print the value.

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Answer:

The solution code is written in Python 3:

  1. def modifyList(listNumber):
  2.    posCount = 0
  3.    negCount = 0
  4.    for x in listNumber:
  5.        if x > 0:
  6.            posCount += 1
  7.        else:
  8.            negCount += 1
  9.    
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  12.    
  13.    if(negCount == len(listNumber)):
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  17. modifyList([-1,-99,-81])
  18. modifyList([1,99,8])
  19. modifyList([-1,99,-81])

Explanation:

The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).

To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).

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If we test our function using the three sets of input list, we shall get the following results:

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