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Cerrena [4.2K]
3 years ago
9

1, 3, 9, 27, ... What's the pattern rule and the next three numbers?​

Mathematics
2 answers:
ddd [48]3 years ago
8 0

Answer:

multiply by three

Step-by-step explanation:

BabaBlast [244]3 years ago
5 0

Step-by-step explanation:

1 x 3 = 3 x 3 = 9 x 3 = 27

=> Pattern rule = 3^{n-1}

=> The next three numbers = 81 , 243 , 729

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Pls help me with this question!!!
ankoles [38]

Answer: $2/child and $4/adult

Step-by-step explanation:

The total fare is $14 for 2 adults and 3 children

x is the child's fare

y is the adults fare

We can say:

1)  3x + 2y = $14

2)  We are told that x = (1/2)y  [each child's fare is 1/2 each adult's fare]

3) use (2) in (1)

  3x + 2y = $14

  3(1/2)y + 2y = $14

 (3/2)y + 2y = $14

  (7/2)y = $14

  y = ($14)*(2/7)

  y = $4/adult

   x = (1/2)y; x = (1/2)(4)

   x = $2/child

Check:  Does 3x + 2y = $14 when x = $2/child and y = $4/adult?

    3x + 2y = $14

    3($2/child) + 2($4/adult) = $14

      $6   +   $8 = $14   YES

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3 years ago
What is the purpose of life?
Novay_Z [31]
In my religion, I believe life is a test from God. 
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4 years ago
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Randomly split the messages into a training set D1 (80% of messages) and a testing set D2 (20% of messages). Calculate the testi
Blizzard [7]

Answer:

In the step-by-step

Step-by-step explanation:

This is the code i created using the R software and the packages "caret" and "e0171".

The script was supposed to work in all general cases.

library(caret)

library(e1071)

# Categorical vector

spam <- c("spam","not_spam")

spam_vec <- sample(spam,60, replace = T)

# Supposing two independent variables so that the kappa will be close to 0.

x1 <- rnorm(60)

x2 <- rnorm(60)

# Creating the dataset

data1 <- cbind(spam_vec,x1,x2)

data1 <- as.data.frame(data1)

names(data1) <- make.names(c("spamvec","x","y"))

# Creating the partition

index <- createDataPartition(data1$spamvec,

                            p=0.8, list=FALSE)

training_data <- data1[index,]

testing_data <- data1[-index,]

fitControl <- trainControl(method = "cv",

                         number = 5,

                         savePred = TRUE,

                         classProb = TRUE)

tune.grid <- expand.grid(C = seq(0, 10, .1))

# Scaling the predictors

preProcess_cs <- preProcess(training_data[, -1],

                                 method = c("center", "scale"))

spam_training_cs      <- predict(preProcess_cs, training_data)

spam_testing_cs       <- predict(preProcess_cs, testing_data)

# Training a Naive Bayes to predict binary outcome

Naive_Bayes_Model=naiveBayes(spamvec ~.,

                            data=spam_training_cs,

                            tuneGrid = tune.grid,

                            trControl = fitControl)

# Confusion matrix

prediction <- predict(Naive_Bayes_Model, spam_testing_cs)

confusionMatrix(prediction, spam_testing_cs$spamvec, positive = "spam")

confM <- confusionMatrix(prediction, spam_testing_cs$spamvec, positive = "spam")

accuracy <- confM$overall[1]

accuracy

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3 years ago
Please ignore my workings.
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After my calculation buckets weight is 2,6 kg
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I dunno can you help me?? please!
Evgesh-ka [11]

Answer:

Yes, this is a function because none of the y values have 2 x values connected to them.

7 0
3 years ago
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