Area of triangle where A=50, b=31, c=18
1 answer:
Use Heron's Formula:
s means semi-perimeter = (50 + 31 + 18) / 2 = 99 / 2 =
49.5
area = sq root [(s * (s-a) * (s-b) * (s-c)]
area = sq root [(49.5 * (s-a) * (s-b) * (s-c)]
This will NOT form a triangle. The longest side (50) is greater than the sum of the other 2 sides.
Source:
http://www.1728.org/trianinq.htm
s means semi-perimeter = (50 + 31 + 18) / 2 = 99 / 2 =
49.5
area = sq root [(s * (s-a) * (s-b) * (s-c)]
area = sq root [(49.5 * (s-a) * (s-b) * (s-c)]
This will NOT form a triangle. The longest side (50) is greater than the sum of the other 2 sides.
Source:
http://www.1728.org/trianinq.htm
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Greetings from Brasil...
According to the statement of the question, we can assemble the following system of equation
X = 7 + 3Y i
X + Y = 75 ii
So, multiplying ii by -1 and adding with i
X = 7 + 3Y
- X - Y = - 75
- Y = 7 + 3Y - 75
4Y = 68
Y = 17
for X we will use ii:
X + Y = 75
X + 17 = 75
X = 58
The smaller number is: 17
