So <u>no solution</u>
Area of triangle where A=50, b=31, c=18
1 answer:
Use Heron's Formula:
s means semi-perimeter = (50 + 31 + 18) / 2 = 99 / 2 =
49.5
area = sq root [(s * (s-a) * (s-b) * (s-c)]
area = sq root [(49.5 * (s-a) * (s-b) * (s-c)]
This will NOT form a triangle. The longest side (50) is greater than the sum of the other 2 sides.
Source:
http://www.1728.org/trianinq.htm
s means semi-perimeter = (50 + 31 + 18) / 2 = 99 / 2 =
49.5
area = sq root [(s * (s-a) * (s-b) * (s-c)]
area = sq root [(49.5 * (s-a) * (s-b) * (s-c)]
This will NOT form a triangle. The longest side (50) is greater than the sum of the other 2 sides.
Source:
http://www.1728.org/trianinq.htm
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