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Bas_tet [7]
3 years ago
15

Write a procedure named Read10 that reads exactly ten characters from standard input into an array of BYTE named myString. Use t

he LOOP instruction with indirect addressing, and call the ReadChar procedure from the book's link library. (ReadChar returns its value in AL.)
Computers and Technology
1 answer:
MatroZZZ [7]3 years ago
3 0

Answer:

Following are the solution to the given question:

Explanation:

Since a procedure has the Read10 parameter, the 10 characters from the input file are stored in the BYTE array as myString. The LOOP instruction, which includes indirect addressing and also the call to the ReadChar method, please find the attached file of the procedure:

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Write the program to solve quadratic equations, but if the discriminant is negative, output
Firdavs [7]

Answer:

PROGRAM  QuadraticEquation Solver

  IMPLICIT  NONE

REAL :: a, b, c ;

  REA :: d ;

  REAL  :: root1, root2 ;

//read in the coefficients a, b and c

  READ(*,*)    a, b, c  

  WRITE(*,*)   'a = ', a

  WRITE(*,*)   'b = ', b

  WRITE(*,*)    'c = ', c

  WRITE(*,*)

// computing the square root of discriminant d

  d = b*b - 4.0*a*c

  IF (d >= 0.0) THEN              //checking if it is solvable?

     d     = SQRT(d)

     root1 = (-b + d)/(2.0*a)     // first root

     root2 = (-b - d)/(2.0*a)     // second root

     WRITE(*,*)  'Roots are ', root1, ' and ', root2

  ELSE                            //complex roots

     WRITE(*,*)  'There is no real roots!'

     WRITE(*,*)  'Discriminant = ', d

  END IF

END PROGRAM  QuadraticEquationSolver

8 0
3 years ago
Students working at individual PCs in a computer laboratory send their files to be printed by a server that spools the files on
Vanyuwa [196]

Answer:

Explanation:

Disk space is a limited resource on the spooling partition and once it is filled the will cause a deadlock. Every single block that comes into the spooling partition claims a resource, and the one behind that wants resources as well, and so on. Since the spooling space is limited and half of the jobs arrive and fill up space then no more blocks can be stored, causing a deadlock. This can be prevented allowing one job to finish and releasing the space for the next job.

5 0
3 years ago
Question 2 In this question you are asked to calculate probabilties for the discrete uniform and exponential distribution. Make
sasho [114]

Answer:

Hi there! The question is asking to make changes to the H3_Q2.java program however there is no such program attached. Nevertheless, the requirements in the question can be addressed in a new H3_Q2.java program that i've listed below.

Explanation:

We can use the Scanner util in Java for prompting user input. The method nextInt() and nextDouble() allow only values of types "int" and "double" respectively. I have used the "switch" statement to direct the program based on user selection of menu item. The checks are printed with the "System.out.println" command and the program exits in case of error or invalid input. Finally, the calculation of probability simply requires you to replace the comment with the formula for the probability calculation based on the method chosen.

H3_Q2.java

import java.util.Scanner;

public class H3_Q2 {

 public static void main(String args[]) {

   // print main menu for user selection

   System.out.println("Please type 1 to select 'discrete uniform' or 2 to select 'exponential'");

   Scanner scan = new Scanner(System.in);

   int selection = scan.nextInt();

   switch(selection) {

     case 1:

       // discrete uniform

       System.out.println("Please enter a lower bound value a: ");

       int a = scan.nextInt();

       System.out.println("Please enter a upper bound value b: ");

       int b = scan.nextInt();

       System.out.println("Please enter a value x: ");

       int x = scan.nextInt();

       if (b <= a) {

         System.out.println("The upper bound value b should be greater than the lower bound value a");

         System.exit(0);

       }

       if (a > x) {

         System.out.println("The value x should be greater than the lower bound value b");

         System.exit(0);

       }

       if (b < x) {

         System.out.println("The value x should be greater than the lower bound value b");

         System.exit(0);

       }

       break;

     case 2:

       // exponential

       System.out.println("Please enter a lambda value for exponential: ");

       double lambda = scan.nextDouble();

       System.out.println("Please enter a value x: ");

       double d_x = scan.nextDouble();

       if (d_x <= 0.0) {

         System.out.println("The value x should be greater than 0");

         break;

       } else {

         // calculate P(X = x) and P(X ≤ x)

         // result = calculateExponential()

         System.out.println("The calculation for the exponential method given the lambda value " + lambda + " and the value of x " + d_x + " is: ");

       }

       break;

     default:

       System.out.println("Invalid input. Exiting..");

       break;

   }

 }

}

7 0
3 years ago
I want to do is speed test to do i go to for my computer
laiz [17]

I just go to the speed test on my browser

7 0
3 years ago
For the question below, refer to the following recursive factorial method.
Romashka-Z-Leto [24]

Answer:

B) (x<=1)

Explanation:

Though this code given will run perfectly without any requirement of base case.But still we have to include a base case I will suggest (x<=1) because the value of x is decreased by one at each recursive call so it can handle it very well and it can handle negative values of x also if user enters it by mistake since factorial is for positive numbers only.

7 0
3 years ago
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