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AnnyKZ [126]
3 years ago
13

Describe how to round 3.987 to the nearest tenth.​

Mathematics
2 answers:
Inga [223]3 years ago
4 0

Answer:

4

Step-by-step explanation:

You see the hunderth digit has a 8, so you round up. 0.9+0.1=1 so you add 1 to 3, so 3.987 rounded is 4

Zanzabum3 years ago
3 0
To round it to the nearest tenth you have to look at the number beside the tenths place and if that number is 5 or above u round the tenths place up. So since that number is an 8 u round the 9 to 0 which then changes the 3 to 4 so your final answer should be 4.0
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(1+x^2)dy/dx+2xy-4x^2=0 bu using Bernoulli's Equation
erastovalidia [21]
Not of Bernoulli type, but still linear.

(1+x^2)\dfrac{\mathrm dy}{\mathrm dx}+2xy=4x^2

There's no need to find an integrating factor, since the left hand side already represents a derivative:

\dfrac{\mathrm d}{\mathrm dx}[(1+x^2)y]=(1+x^2)\dfrac{\mathrm dy}{\mathrm dx}+2xy

So, you have

\dfrac{\mathrm d}{\mathrm dx}[(1+x^2)y]=4x^2

and integrating both sides with respect to x yields

(1+x^2)y=\displaystyle\int4x^2\,\mathrm dx
(1+x^2)y=\dfrac43x^3+C
y=\dfrac{4x^3}{3(1+x^2)}+\dfrac C{1+x^2}
7 0
3 years ago
Which fraction is bigger 1/3 or 2/6. Explain
NikAS [45]
They are equal.

2/6 = 1/3

1 * 2 = 2
        -------
3 * 2 = 6 

do you see it?
5 0
3 years ago
What is the mean, median, mode, and range of 8, 35, 10, 12, 14?
Ivan

answer:

mean: 15.8

median: 12

mode: no mode

range: 27

step-by-step explanation:

  • first know how to find each of the above and what they are
  • mean = (avg) add all the numbers, then divide by the number of numbers
  • median = the middle number from increasing order
  • mode = the one that repeats the most
  • range = the difference between the largest and smallest number

8, 35, 10, 12, 14

<u>mean</u>

8 + 35 + 10 + 12 + 14 = 79

  • there are five numbers

79 / 5 = 15.8

<u>median</u>

  • put them from smallest to largest

8, 10, 12, 14, 35

  • 12 is the median OR the middle number

<u>mode</u>

  • no number repeat, so no mode

<u>range</u>

35 - 8 = 27

3 0
3 years ago
How do I find a2 and a3 for the following geometric sequence? 54, a2, a3, 128
vlada-n [284]
The formula for the nth term of a geometric sequence:
a_n=a_1 \times r^{n-1}
a₁ - the first term, r - the common ratio

54, a_2, a_3, 128 \\ \\&#10;a_1=54 \\&#10;a_4=128 \\ \\&#10;a_n=a_1 \times r^{n-1} \\&#10;a_4=a_1 \times r^3 \\&#10;128=54 \times r^3 \\&#10;\frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\&#10;\frac{64}{27}=r^3 \\&#10;\sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\&#10;\frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\&#10;r=\frac{4}{3}

a_2=a_1 \times r= 54 \times \frac{4}{3}=18 \times 4=72 \\&#10;a_3=a_2 \times r=72 \times \frac{4}{3}=24 \times 4=96 \\ \\&#10;\boxed{a_2=72, a_3=96}
7 0
3 years ago
Read 2 more answers
N/-1.5 = -1.2 DO NOT round the solution
wariber [46]
N = -1.5 * -1.2 = 1.8
3 0
3 years ago
Read 2 more answers
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