All categories

3 years ago

The population of Minnesota in thousands, t years since 2000 can be represented by P=37t+4934.

Mathematics

1 answer:

pychu [463]3 years ago

5 0

Answer(A):

Given that the population of Minnesota in thousands, t years since 2000 can be represented by equation:

P=37t+4934

P-intercept means value of P when t=0

P=37*0+4934

P=0+4934

P=4934

Hence P-intercept is 4934. Which means that population of Minnesota in year 2000 was 4934.

Answer(B):

t-intercept means value of t when P=0

0=37t+4934

-4934=37t

divide by 37

-4934/37=t

-133.351351351 = t

Hence t-intercept is -4934/37 which is approx -133. Which means that population of Minnesota in year (2000-133) that is in year 1867 was 0.

You might be interested in

A video game randomly chooses your car color and type. The probability of getting a red car is 0.25, and the probability of gett

EleoNora [17]

In probability 2 events are independent if the occurrence of 1 event does not affect the occurrence of the other event. Mathematically, if event A and event B are independent, then $P(A\&B)=P(A)\times P(B)$ . For our two events in this problem we have that $P(A)=0.25$ and $P(B)=0.40$ . If these two events are independent, then we should have that,

$P(A\&B)=P(A)\times P(B)\\P(A\times B)=0.25\times 0.4=0.1.$

.A and B are independent events if the probability of A and B is 0.1

6 0

3 years ago

Read 2 more answers

How many ms in a second?

professor190 [17]

1000. its making me type more stuff

4 0

1 year ago

Use function notation that describes the value of the function m at x

mr_godi [17]

Answer:

A function is a relation in which each possible input value leads to exactly one output value. We say “the output is a function of the input.”

The input values make up the domain, and the output values make up the range.

Step-by-step explanation:

5 0

3 years ago

The mean cost of a five pound bag of shrimp is 40 dollars with a standard deviation of 7 dollars. If a sample of 51 bags of shri

eimsori [14]

Answer:

$P(|\bar{x}-40| > 0.6)=0.5404$

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 40 dollars

Standard Deviation, σ = 7 dollars

Sample size,n = 51

We are given that the distribution of cost of shrimp is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{7}{\sqrt{51}} = 0.9801$

P(sample mean would differ by true mean by more than 0.6)

$P(|\bar{x}-40| > 0.6)\\\Rightarrow = 1-P(39.4$

$P(39.4 \leq x \leq 40.6) \\\\= P(\displaystyle\frac{39.4 - 40}{0.9801} \leq z \leq \displaystyle\frac{40.6-40}{0.9801})\\\\ = P(-0.6121 \leq z \leq 0.6121)\\= P(z \leq 0.6121) - P(z < -0.6121)\\= 0.7298 - 0.2702 =0.4596$