Answer:
A) З x,y : ( x/y < 1, y/x < 1 )
B) ∀ Y : ( Y > 0 = 1/Y > 0 )
C) з x,y : ( x+y = xy )
D) ∀ x,y : [ ( x>0 ) ∧( y > 0 ) = (( x/y > 0 ) ∧ ( y/x > 0 ))
E ) ∀ y : [ ( y > 0 ) ∧ ( y < 1) = ( 1 / y > 1 )
F) <em>n</em> ( ( з x ∀ y ( x <y ) )
G) ∀x (( x ≠ 0 ) = ( зy ( xy = 1 ) ))
H) ∀x ( (x≠0) = ( з! y (xy = 1))
Step-by-step explanation:
since the domain of discourse is a set of all real numbers the logical expressions of the English statements are expressed with respect to real number:
A) З x,y : ( x/y < 1, y/x < 1 )
B) ∀ Y : ( Y > 0 = 1/Y > 0 )
C) з x,y : ( x+y = xy )
D) ∀ x,y : [ ( x>0 ) ∧( y > 0 ) = (( x/y > 0 ) ∧ ( y/x > 0 ))
E ) ∀ y : [ ( y > 0 ) ∧ ( y < 1) = ( 1 / y > 1 )
F) <em>n</em> ( ( з x ∀ y ( x <y ) )
G) ∀x (( x ≠ 0 ) = ( зy ( xy = 1 ) ))
H) ∀x ( (x≠0) = ( з! y (xy = 1))
