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2 years ago

Write an equation of the line that is perpendicular to 2x+4y=-6 and passes through the point (2,5).

Mathematics

1 answer:

wolverine [178]2 years ago

7 0

Answer:

y=2x+1

Step-by-step explanation:

Perpendicular equation has a negative inverse of the slope from the original equation. This basically mean you get the slope, flip the numerator and denominator, and flip the sign.

Once you get the slope for the perpendicular equation, you plug it into the point-slop formula and simply.

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Pleaseee helpppp answer correctly !!!!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!

kirza4 [7]

Answer:

10.4 meters

Step-by-step explanation:

3 0

2 years ago

In a class full of men and women, 5/9 of the class are women. What is the ratio of men to women in its simplest form?

andrew-mc [135]

Answer:

4/5

Step-by-step explanation:

5x are women

9x are full class

9x - 5x = 4x

4x are men

$\frac{4x}{5x} = \frac{4}{5}$ is the ratio of men to women in its simplest form

Hope this helps ^-^

3 0

2 years ago

Consider the equation:

Alenkasestr [34]

Answer:

the equation is not correct....

well, it should look sth. like (x+or- number)^2=number

5 0

2 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

2 years ago

What the quotient of <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%5Cdiv%20%20%5Cfrac%7B1%7D%7B8%7D%20%20" i

balandron [24]

The correct answer is 6!

5 0

2 years ago