The pool has a diameter 20 ft so: r = 10 ft.
The pool cover extents 12 inches beyond the edge of the pool.
12 inches = 1 foot
Therefore, the radius of the pool cover is : r = 10 + 1 = 11 ft.
a. The area of the pool cover:
A = r² π = 11² π = 121 π ft²
b. The length of the rope:
l = 2 r π = 2 · 11 π = 22 π ft.
I don’t understand what you’re saying ?
Answer:
![[0, 3, -6]](https://tex.z-dn.net/?f=%5B0%2C%203%2C%20-6%5D)
Step-by-step explanation:
{4x + y = 3
{x + y - z = 9 ←
{2x + 2y + z = 0 ←
{4x + y = 3
{3x + 3y = 9 >> Combined equation
−¾[4x + y = 3]
{−3x - ¾y = −2¼ >> New Equation
{3x + 3y = 9
_________
2¼y = 6¾
___ ___
2¼ 2¼
[Plug this back into all three equations to get the z-value of −6, and the x-value of 0];
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Answer:
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Step-by-step explanation:
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