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zysi [14]
3 years ago
15

Which of the following qualities of large man-made structures is unique to dams? They span water bodies They generate electricit

y They can withstand wind They can withstand bending​
Engineering
2 answers:
Anna11 [10]3 years ago
8 0

They generate electricity.

IRINA_888 [86]3 years ago
7 0

Answer:

Generate Electricity

Explanation:

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Modulus of resilience is: (a) Slope of elastic portion of stress- strain curve (b) Area under the elastic portion of the stress-
Vedmedyk [2.9K]

Answer: b) Area under the elastic portion of the stress-strain curve

Explanation:

By definition, resilience is the strain-energy density stored by the material when it is stressed to the proportional limit defined by Hooke's Law. Resilience is given by the following expression:

μ(r) = \sigma(pl)^{2} / 2E

μ(r) is the modulus of resilience

σ(pl) is the stress to the proportional limit

E is the elastic modulus

When you look at the stress-strain curve, the area under the elastic portion (up to the proportional limit) can be obtained by the area of a triangle with base equal to the strain (σ) and height equal to the stress (ε):

Ω = (b . h) / 2 = (σ(pl) . ε) / 2

Using Hooke's Law: σ = E . ε  → ε = σ/E

Replacing the expression in the area equation:

Ω = (σ(pl) . ε) / 2 = \sigma(pl)^{2} / 2E = μ(r)

3 0
3 years ago
5. Can you still prepare solutions using available materials at home why​
svetoff [14.1K]
Yes, we can by the proper guidance and proper doing. We can create solution by any materials in the house that you need
7 0
3 years ago
PLEASE HELP, TEST MULTIPLE CHOICE QUESTIONS
Rina8888 [55]

Answer:

c

Explanation:

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8 0
3 years ago
Read 2 more answers
Multiply each element in origList with the corresponding value in offsetAmount. Print each product followed by a space.Ex: If or
n200080 [17]

Answer:

Here is the JAVA program:  

import java.util.Scanner; // to take input from user

public class VectorElementOperations {

public static void main(String[] args) {

final int NUM_VALS = 4; // size is fixed that is 4 and assigned to NUM_VALS

int[] origList = new int[NUM_VALS];

int[] offsetAmount = new int[NUM_VALS];

int i;

//two lists origList[] and offsetAmount[] are assigned values

origList[0] = 20;

origList[1] = 30;

origList[2] = 40;

origList[3] = 50;

offsetAmount[0] = 4;

offsetAmount[1] = 6;

offsetAmount[2] = 2;

offsetAmount[3] = 8;

String product=""; // product variable to store the product of 2 lists

for(i = 0; i <= origList.length - 1; i++){

/* loop starts with i at 0th position or index and ends when the end of the origList is reached */

/* multiples each element of origList to corresponding element of offsetAmount and stores result in the form of character string in product*/

   product+= Integer.toString(origList[i] *= offsetAmount[i]) + " ";  }

 System.out.println(product); }}   //displays the product of both lists

Output:

80 180 80 400

Explanation:

If you want to print the product of origList with corresponding value in offsetAmount in vertical form you can do this in the following way:

import java.util.Scanner;

public class VectorElementOperations {

public static void main(String[] args) {

final int NUM_VALS = 4;

int[] origList = new int[NUM_VALS];

int[] offsetAmount = new int[NUM_VALS];

int i;

origList[0] = 20;

origList[1] = 30;

origList[2] = 40;

origList[3] = 50;

offsetAmount[0] = 4;

offsetAmount[1] = 6;

offsetAmount[2] = 2;

offsetAmount[3] = 8;

for(i = 0; i <= origList.length - 1; i++){

 origList[i] *= offsetAmount[i];

System.out.println(origList[i]); } }}

Output:

80                                                                                                                            

180                                                                                                                          

80                                                                                                                            

400

The program along with the output is attached as screenshot with the input given in the example.

8 0
3 years ago
A laboratory in the Y building keep a vacuum pressure of 0.1 kPa abs. What is the net force acting on the door considering the a
seropon [69]

Answer:

net force acting on the floor is 100 kN

Explanation:

Given data:

P_{vaccum} = 0.1 kPa

P_{atm} = 101.325 kPa

dimension of floor = 2 m \times 0.5 m

we know that

Net force can be calculated as follow

f_{net} = P_{vaccum} \times area

f_{net} = 0.1\times 10^3 \times 2\times 0.5

f_{net} = 0.1\times 10^3 \times 1

f_{net} = 100 kN

Therefore net force acting on the floor is 100 kN

7 0
4 years ago
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