The work done on the gas during this process if the final pressure is 456 kPa is; -82.8 kJ
<h3>Workdone in Thermodynamics</h3>
We are given;
The initial pressure; P₁ = 96 kPa
Final Pressure; P₂ = 456 kPa
The gas is compressed according to;
p = aV + b
where;
a = -1200 kPa/m³
b = 600 kPa
Thus, at initial pressure P₁ = 96 kPa;
96 = -1200V₁ + 600
1200V₁ = 600 - 95
1200V₁ = 505
V₁ = 505/1200
V₁ = 0.42 m³
At Final Pressure P₂ = 456 kPa;
456 = -1200V₂ + 600
1200V₂ = 600 - 456
1200V₂ = 144
V₂ = 144/1200
V₂ = 0.12 m³
Formula for the workdone during the process is;
W_out = ¹/₂(P₁ + P₂)(V₂ - V₁)
W_out = ¹/₂(96 + 456)(0.12 - 0.42)
W_out = -82.8 kJ
Read more about workdone in thermodynamics at; brainly.com/question/12641937
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Answer:
Ts = 413.66 K
Explanation:
given data
temperature = 20°C
velocity = 10 m/s
diameter = 5 mm
surface emissivity = 0.95
surrounding temperature = 20°C
heat flux dissipated = 17000 W/m²
to find out
surface temperature
solution
we know that here properties of air at 70°C
k = 0.02881 W/m.K
v = 1.995 × m²/s
Pr = 0.7177
we find here reynolds no for air flow that is
Re =
Re =
Re = 2506
now we use churchill and bernstein relation for nusselt no
Nu = = 0.3 +
h = 0.3 +
h = 148.3 W/m².K
so
q conv = h∈(Ts- T∞ )
17000 = 148.3 ( 0.95) ( Ts - (20 + 273 ))
Ts = 413.66 K
Answer:
The capacity of the sludge pump is 0.217 m3/min
Explanation:
Solution is attached below