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3 years ago

PLS HELP

Mathematics

1 answer:

uysha [10]3 years ago

4 0

Answer:

The option which represents the inequality is option D ; stated as x ≥ 0

Step-by-step explanation:

The marked or dotted position is 0 ; which represents the position of x, when graphing inequality statements, if the point IS SHADED, then it means GREATER THAN EQUAL TO.

Option A is incorrect, the inequality sign is not the same as the direction of the arrow.

Option B, says LESS THAN EQUAL TO, instead of GREATER THAN EQUAL TO

Option C SAYS GREATER THAN instead of GREATER THAN EQUAL TO.

Therefore, Option D is the correct expression which means x is GREATER THAN EQUAL TO.

Learn more : brainly.com/question/24065770

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A point is an exact location that has no size or dimension. True or False?

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It's true because a pint is used to locate co-ordinates and has no size or dimension

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3 years ago

Read 2 more answers

(08.07 HC)

andreev551 [17]

Answer:

$\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}$

$\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

C) See attachment.

Step-by-step explanation:

Given function:

$f(x)=2x^2-x-10$

To factor a <u>quadratic</u> in the form $ax^2+bx+c$ <em> , </em>find two numbers that multiply to $ac$ and sum to $b$ :

$\implies ac=2 \cdot -10=-20$

$\implies b=-1$

Therefore, the two numbers are -5 and 4.

Rewrite $b$ as the sum of these two numbers:

$\implies f(x)=2x^2-5x+4x-10$

Factor the first two terms and the last two terms separately:

$\implies f(x)=x(2x-5)+2(2x-5)$

Factor out the common term (2x - 5):

$\implies f(x)=(x+2)(2x-5)$

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

$\implies (x+2)(2x-5)=0$

Therefore:

$\implies (x+2)=0 \implies x=-2$

$\implies (2x-5)=0 \implies x=\dfrac{5}{2}$

So the x-intercepts are:

$x=-2, \:\:x=\dfrac{5}{2}$

The x-value of the vertex is:

$\implies x=\dfrac{-b}{2a}$

Therefore, the x-value of the vertex of the given function is:

$\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}$

To find the y-value of the vertex, substitute the found value of x into the function:

$\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}$

Therefore, the vertex of the function is:

$\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards. This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>. Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

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Write everything on one side
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3 years ago

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AveGali [126]

Answer:

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Step-by-step explanation:

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3 years ago

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Korolek [52]

Answer:

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Step-by-step explanation:

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y=3x-15

Interchange x and y

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3 years ago