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SSSSS [86.1K]
3 years ago
13

Please help!!!!

Mathematics
1 answer:
Irina18 [472]3 years ago
8 0

Number of trees infected after t years:

The number of trees infected after t years is given by:

f(t) = e^{0.4t}

Question 1:

We have to find the number of years it takes to have 21 trees infected, that is, t for which:

f(t) = 21

Thus:

e^{0.4t} = 21

To isolate t, we apply the natural logarithm to both sides of the equation, and thus:

\ln{e^{0.4t}} = \ln{21}

0.4t = \ln{21}

t = \frac{\ln{21}}{0.4}

t = 7.6

Thus, it will take 7.6 years for 21 of the trees to become infected.

Question 2:

We have to find the inverse function, that is, first we exchange y and x, then isolate x. So

f(x) = y = e^{0.4x}

e^{0.4y} = x

Again, we apply the natural logarithm to both sides of the equation, so:

\ln{e^{0.4y}} = \ln{x}

0.4y = \ln{x}

g(x) = \frac{\ln{x}}{0.4}

Thus, the logarithmic model is:

g(x) = \frac{\ln{x}}{0.4}

For an example of a problem that uses exponential functions and logarithms, you can take a look at brainly.com/question/13812761

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Sam takes x minutes yo walk from home to library and 5 minutes more to walk from the library to school than fron home to the lib
LuckyWell [14K]

Answer:

2x+5\ minutes

Step-by-step explanation:

Given:

Sam takes x minutes yo walk from home to library.

And takes 5 minutes more to walk from the library to school than from home to the library.

Express the total time taken for Sam to walk from home to school via the library in terms of x.

<u>Solution:</u>

Time taken by Sam to walk from home to library = x\ minutes

Time taken by Sam to walk from library to school = x+5\ minutes

Total time taken by Sam to walk from home to school via the library = Time taken to walk from home to library + Time taken to walk from library to school

Total time taken = x+x+5=2x+5

Therefore, the total time taken for Sam to walk from home to school via the library is 2x+5\ minutes

8 0
3 years ago
The probability density function of the time you arrive at a terminal (in minutes after 8:00 A.M.) is f(x) = 0.1 exp(−0.1x) for
Blababa [14]

f_X(x)=\begin{cases}0.1e^{-0.1x}&\text{for }x>0\\0&\text{otherwise}\end{cases}

a. 9:00 AM is the 60 minute mark:

f_X(60)=0.1e^{-0.1\cdot60}\approx0.000248

b. 8:15 and 8:30 AM are the 15 and 30 minute marks, respectively. The probability of arriving at some point between them is

\displaystyle\int_{15}^{30}f_X(x)\,\mathrm dx\approx0.173

c. The probability of arriving on any given day before 8:40 AM (the 40 minute mark) is

\displaystyle\int_0^{40}f_X(x)\,\mathrm dx\approx0.982

The probability of doing so for at least 2 of 5 days is

\displaystyle\sum_{n=2}^5\binom5n(0.982)^n(1-0.982)^{5-n}\approx1

i.e. you're virtually guaranteed to arrive within the first 40 minutes at least twice.

d. Integrate the PDF to obtain the CDF:

F_X(x)=\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=\begin{cases}0&\text{for }x

Then the desired probability is

F_X(30)-F_X(15)\approx0.950-0.777=0.173

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Answer:

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A pharmacist who wants to mix 836% solution with a 12% saline solution to get 64 mL at 33% saline solution how much of each solu
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What is the answer to 3x+2y=14
lord [1]

Answer:

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Step-by-step explanation:

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Divide both sides by 3:

Answer:  x = 14/3 - (2 y)/3

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