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2 years ago

What is the volume of the cone below?

Mathematics

1 answer:

Serjik [45]2 years ago

5 0

Answer:

B. 264π units³

Step-by-step explanation:

Volume of the cone = ⅓πr²h

Where,

r = 6

h = 22

Plug in the values

Volume = ⅓×π×6²×22

Volume = ⅓×π×36×22

Volume = 264π units³

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Plz help me with this ASAP

VLD [36.1K]

Answer:

Step-by-step explanation:

plug all in

1) 0 when x=0

2) 1*6-1²=6-1=5

3) 6*2-2²=12-4=8

4)6*3-3²=18-9=9

5) 6*4-4²=24-16=8

6)6*5-5²=30-25=5

7) 6*6-6²=36-36=0

6 0

3 years ago

Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]

JulijaS [17]

Answer:

$f_{avg}=\frac{1}{e-1}$

Step-by-step explanation:

We are given that a function

$f(x)=2lnx$

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx$

By Parts integration formula

$\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx$

u=ln x and v=dx

Apply by parts integration

$f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))$

$f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})$

$f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}$

By using property lne=1,ln 1=0

$f_{avg}=\frac{1}{e-1}$

8 0

2 years ago

Find the sum of (x+5), (-4x-2), and (2x-1)

RideAnS [48]

I think the answer is -x+2.

3 0

3 years ago

Select the equation written in point-slope form.

slavikrds [6]

Poin slope form is
y-y1=m(x-1)
the answer is A

4 0

3 years ago

1. (01.02)

Anton [14]

Answer:4

Step-by-step explanation:

f(1)=6(1)+2

g(f(1))=2(8)+4/5

=20/5

6 0

2 years ago