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patriot [66]
2 years ago
8

The sum of 4 + 9 times a number algebraic expression​

Mathematics
1 answer:
azamat2 years ago
3 0

Answer:

(4+9)x=_

Step-by-step explanation

you have your 4+9 in parenthesis, meaning its one of the things to answer first, the x meaning there is a number to multiply  4+9 by.

Hope this helps!

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s = 6t² + 3t + 7, 0 ≤ t ≤ 2 Find the body's displacement and average velocity for the given time interval.
Lapatulllka [165]

Answer:

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4 0
3 years ago
The circumference of a circle is 251.2 millimeters. What is the circle's diameter? Use 3.14 for it.​
Bas_tet [7]

Answer:

80

Step-by-step explanation:

divide the circumference (251.2) by pi (3.14) and get 80

3 0
3 years ago
A line includes the points (13,15) and (6,15). What is its equation in slope-intercept form?​
Andrew [12]

Answer:

y=15

Step-by-step explanation:

y=mx+b

slope(y2-y1)/(x2-x1)

(15-15)/(6-13)

0/-7=0

y-intercept 15=0(15)+b

b=15

y=15

6 0
3 years ago
Let S be the surface defined by x 2 + 2y 3 + 3z 4 = 6. Let T be the surface defined parametrically by r(u, v) = (1+ln u, 2e v+u−
aleksandrvk [35]

The tangent to C through (1, 1, 1) must be perpendicular to the normal vectors to the surfaces S and T at that point.

Let f(x,y,z)=x^2+2y^3+3z^4. Then S is the level curve f(x,y,z)=6. Recall that the gradient vector is perpendicular to level curves; we have

\nabla f(x,y,z)=(2x,6y,12z^2)

so that the gradient of f at (1, 1, 1) is

\nabla f(1,1,1)=(2,6,12)

For the surface T, we have

\begin{cases}1+\ln u=1\\2e^v+u-2=1\\uv+1=1\end{cases}\implies u=1,v=0

so that \vec r(1,0)=(1,1,1). We can obtain a vector normal to T by taking the cross product of the partial derivatives of \vec r(u,v), and evaluating that product for u=1,v=0:

\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left(u-2ve^v,-1,\dfrac{2e^v}u\right)

\left(\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right)(1,0)=(1,-1,2)

Now take the cross product of the two normal vectors to S and T:

(2,6,12)\times(1,-1,2)=(24,8,-8)

The direction of vector (24, 8, -8) is the direction of the tangent line to C at (1, 1, 1). We can capture all points on the line containing this vector by scaling it by t\in\Bbb R. Then adding (1, 1, 1) shifts this line to the point of tangency on C. So the tangent line has equation

\vec\ell(t)=(1,1,1)+t(24,8,-8)=(1+24t,1+8t,1-8t)

7 0
3 years ago
A construction company purchased seven house lots of the following sizes:
Oksanka [162]

Answer:

between 1 1/8 acres and 2 1/4 acres

Step-by-step explanation:

3 0
3 years ago
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