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Amiraneli [1.4K]
3 years ago
13

Help picture is shown!!!!

Mathematics
2 answers:
daser333 [38]3 years ago
6 0
D,

Symmetry is when you split the shape, but they look the same. 
krok68 [10]3 years ago
3 0
Symmetry, it is split in the middle and both sides are the exact same

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If f(x) = 5x – 2 and g(x) = 2x + 1, find (f- g)(x).
GalinKa [24]

Answer:

la respuesta es A. 3x - 3

7 0
3 years ago
How to write 10.4 as a mixed number in simplest form?
ki77a [65]
The answer to your question is 10 2/5
3 0
2 years ago
a motorcycle dealer paid a certain price for a motorcycle and marked it up by 1/5 of the price he paid. Later, he sold it for $1
katovenus [111]
Okay so $14,000 is the equivalent of 6/5ths
so divide $14,000 by 6= $2333.3r

you need 5/5
so $2333.3r x 5 = $11666.67
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5 0
3 years ago
HELP!!! PLZZ THIS IS SO FRICKIN HARD!
krek1111 [17]

Answer:

14.3%

Step-by-step explanation:

1/7=0.142857142857

round that to the nearest tenth and that is 0.143

make it a percentage and it is 14.3%

8 0
2 years ago
Ok need help this is the question :Use the Pythagorean theorem to write an equation for the distance Jane's trainer bikes.
IRINA_888 [86]

Answer:

<em>Jane traveled 8 miles farther then her trainer</em>

Step-by-step explanation:

<u>The Pythagora's Theorem</u>

In any right triangle, the square of the measure of the hypotenuse is the sum of the squares of the legs. This can be expressed with the formula:

c^2=a^2+b^2

Where

c = Hypotenuse or largest side

a,b = Legs or shorter sides

Jane's path from the Health Club to the end of her route describes two sides of a right triangle of lengths a=16 miles and b=12 miles.

Her total distance traveled is 16 + 12 = 28 miles

Her trainer goes directly from the Health Club to meet her through the hypotenuse of the triangle formed in the path.

We can calculate the length of his route as:

c=\sqrt{16^2+12^2}

c=\sqrt{256+144}=\sqrt{400}=20

c = 20 miles

The difference between their traveled lengths is 28 - 20 = 8 miles

Jane traveled 8 miles farther then her trainer

8 0
3 years ago
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