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3 years ago

Point D is at (-4,-2) on a coordinate plane, what would be the ordered pair if

Mathematics

1 answer:

poizon [28]3 years ago

8 0

Answer:

As such, in first quadrant, both the coordinates (x and y) are positive and both are negative in third quadrant. In second quadrant, y is positive and x is negative, while in fourth quadrant x is positive and y is negative, As (-4, -2) has both x and y coordinates negative, it will be found in third quadrant

Step-by-step explanation:

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Remer 1) 5k? + 10k + 6 = 0

IceJOKER [234]

Ignoring the "?" in your question:

$5k+10k+6=0 \iff 15k+6=0 \iff k=-\dfrac{6}{15}$

If the "?" is a squared symbol that wasn't caught:

$5k^2+10k+6=0$

Use the quadratic formula

$x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

to get the solutions:

$x_{1,2}=\dfrac{-10\pm\sqrt{100-120}}{10}$

as you can see, the discriminant is negative, so the equation has no solution.

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3 years ago

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Marizza181 [45]

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The processed I used to solve is below. If you have an questions let me know!

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How many multiples of 9 are there between 100 and 2,000?

Marat540 [252]

First of all, find the first number more than 100 that can divided by 9, and it's 108 (we'll call it as 'a') then, find the number less than 2000 that can divided by 9, it's 1.998 (we'll call it as 'Un')

Un = a + (n-1).b
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1998 = 108 + 9n -9
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and the total is
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