Answer: 7.07 so 7.1
Step-by-step explanation:
Squares have 4 equal sides which puts each side at being 5. Then to find the diagonal you use sqrt(2)a so the square root of 2 times a which is 5 in this case.
Answer:
6
Step-by-step explanation:
Answer:
(9 - 4 x)/(x (2 x - 4))
Step-by-step explanation:
Simplify the following:
1/(2 x^2 - 4 x) - 2/x
Put each term in 1/(2 x^2 - 4 x) - 2/x over the common denominator x (2 x - 4): 1/(2 x^2 - 4 x) - 2/x = ((x (2 x - 4))/(2 x^2 - 4 x))/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4)):
((x (2 x - 4))/(2 x^2 - 4 x))/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4))
A common factor of 2 x - 4 and 2 x^2 - 4 x is 2 x - 4, so (x (2 x - 4))/(2 x^2 - 4 x) = (x (2 x - 4))/(x (2 x - 4)):
((x (2 x - 4))/(x (2 x - 4)))/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4))
(x (2 x - 4))/(x (2 x - 4)) = 1:
1/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4))
1/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4)) = (1 - 2 (2 x - 4))/(x (2 x - 4)):
(1 - 2 (2 x - 4))/(x (2 x - 4))
-2 (2 x - 4) = 8 - 4 x:
(8 - 4 x + 1)/(x (2 x - 4))
Add like terms. 1 + 8 = 9:
Answer: (9 - 4 x)/(x (2 x - 4))
To change it into slope intercept (y=mx+b) you just replace the inequality with an equality and isolate y
x<=2:
x=2=y-> y=2 or y=2+0x
2x-3y>=4:
2x-3y=4
2x-4=3y
(2/3)x-(4/3))=y
y=(2/3)x-(4/3)
x+y>0:
x+y=0
y=-x or y=-x+0
