Answer:
The 6th degree polynomial is 
Step-by-step explanation:
Zeros of a function:
Given a polynomial f(x), this polynomial has roots 
such that it can be written as: 
, in which a is the leading coefficient.
Zero 1 with multiplicity 3.
So
Zero 4 with multiplicity 2.
Considering also the zero 1 with multiplicity 3.
Zero -3 with multiplicity 1:
Considering the previous zeros:
Degree is the multiplication of the multiplicities of the zeros. So
3*2*1 = 6
The 6th degree polynomial is
The y intercept is= (0,3)
f(x) = 2x + 1 and g(x) = f(x) + 3
g(x) = 2x + 1 + 3
<h2><u>g(x) = 2x + 4</u></h2>
Answer:
• linear angles
• supplementary angles (all linear angles are supplementary)
Step-by-step explanation:
If the angles share a side and are measured in opposite directions from that side, the non-common edges of these angles form a straight line, so these angles are sometimes called "linear" angles.
Since their sum is 180°, they are always "supplementary" angles. (Supplementary angles need not share a vertex or a side.)
Answer:
The statement If ∠A ≅ ∠C not prove that Δ ABD ≅ Δ CBD by SAS ⇒ C
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets solve the problem
- In the 2 triangles ABD , CBD
∵ AB = CB
∵ BD is a common side in the two triangles
- If AD = CD
∴ Δ ABD ≅ Δ CBD ⇒ SSS
- If BD bisects ∠ABC
∴ m∠ABD = m∠CBD
∴ Δ ABD ≅ Δ CBD ⇒ SAS
- If ∠A = ∠C
∴ Δ ABD not congruent to Δ CBD by SAS because ∠A and ∠C
not included between the congruent sides
* The statement If ∠A ≅ ∠C not prove that Δ ABD ≅ Δ CBD by SAS
