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nydimaria [60]
3 years ago
13

Can you help me please?

Mathematics
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:

35 meters.

Step-by-step explanation:

The area formula for a triangle is this:

A=1/2(lw)

So, plug in the numbers...

A=1/2(5*7)

A=18.5

Multiply by 2 to get 35 meters.

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Write the general polynomial p(x) if its only zeros are 1 4 and -3 with multiplicites 3 2 and 1 respectively what is the degree
kompoz [17]

Answer:

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zero 1 with multiplicity 3.

So

p(x) = (x-1)^3

Zero 4 with multiplicity 2.

Considering also the zero 1 with multiplicity 3.

p(x) = (x-1)^3(x-4)^2

Zero -3 with multiplicity 1:

Considering the previous zeros:

p(x) = (x-1)^3(x-4)^2(x-(-3)) = (x-1)^3(x-4)^2(x+3)

Degree is the multiplication of the multiplicities of the zeros. So

3*2*1 = 6

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

8 0
3 years ago
Does the equation x2 - 6x + y2 - 6y = -9 intersect the y-axis
Lana71 [14]
The y intercept is= (0,3)
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If f(x) = 2x + 1 and g(x) = f(x) + 3,<br> what would be the function of g(x)?
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f(x) = 2x + 1 and g(x) = f(x) + 3

g(x) = 2x + 1 + 3

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2 years ago
These are two angles that add up to 180° that share a common vertex. What do you call these angles?
Yuri [45]

Answer:

• linear angles

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Step-by-step explanation:

If the angles share a side and are measured in opposite directions from that side, the non-common edges of these angles form a straight line, so these angles are sometimes called "linear" angles.

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8 0
3 years ago
7HELP________________
tatuchka [14]

Answer:

The statement If ∠A ≅ ∠C not prove that Δ ABD ≅ Δ CBD by SAS ⇒ C

Step-by-step explanation:

* Lets revise the cases of congruence  

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ  

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

 ≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

 and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse  

 leg of the 2nd right angle Δ

* Lets solve the problem

- In the 2 triangles ABD , CBD

∵ AB = CB

∵ BD is a common side in the two triangles

- If AD = CD

∴ Δ ABD ≅ Δ CBD ⇒ SSS

- If BD bisects ∠ABC

∴ m∠ABD = m∠CBD

∴ Δ ABD ≅ Δ CBD ⇒ SAS

- If ∠A = ∠C

∴ Δ ABD not congruent to Δ CBD by SAS because ∠A and ∠C

  not included between the congruent sides

* The statement If ∠A ≅ ∠C not prove that Δ ABD ≅ Δ CBD by SAS

5 0
3 years ago
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