If 36/5x=3/5 find x

When do you use ( P ) in simple interest word problems? i always get Interest ( I ) mixed up with .. i know HOW to solve it but

alexandr1967 [171]

90/2 = 45
45/1700 = 0.02647
0.02647 x 100 = 2.64
2.46%

8 0

3 years ago

Consumer products are required by law to contain at least as much as the amount printed on the package. For example, a bag of po

Troyanec [42]

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, $\sigma=0.2$ ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

$P(x\geq 10)=0.99$

Assume the bag weight distribution is bell-shaped

Therefore,

$P(\frac{x-\mu}{\sigma}\geq 10)=0.99$

We know that

$z=\frac{x-\mu}{\sigma}$

Using the value of z

Now,

$\frac{10-\mu}{0.2}=0.99$

$10-\mu=0.99\times 0.2$

$\mu=10-0.99\times 0.2$

$\mu=9.802$

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

5 0

3 years ago

WORD PROBLEM

Nina [5.8K]

It costs 2.50 for 1 taco and 4 dollars for 1 burrito

5 0

3 years ago

Dionne can fold 175 packing boxes in 50 mìnutes. Elias can fold 120 packing boxes in 40 minutes. How long will it take each pers

Gre4nikov [31]

<h2>Dionne will fold 210 packing boxes in "60 mìnutes" and</h2><h2>Elias will fold 210 packing boxes in "70 mìnutes".</h2>

Step-by-step explanation:

Given,

Dionne can fold 175 packing boxes = 50 mìnute and

Elias can fold 120 packing boxes = 40 minutes

To find, the total time each person to fold 210 packing boxes = ?

∵ Dionne can fold 175 packing boxes = 50 mìnute

∴ In 1 mìnute, Dionne can fold number of packing boxes = $\dfrac{175}{50}$ = 3.5

∴ Dionne can fold 210 packing boxes = $\dfrac{210}{3.5}$ minutes

= 60 minutes

Also,

Elias can fold 120 packing boxes = 40 minutes

∴ In 1 mìnute, Elias can fold number of packing boxes = $\dfrac{120}{40}$ = 3

∴ Elias can fold 210 packing boxes = $\dfrac{210}{3}$ minutes

= 70 minutes

Thus, Dionne will fold 210 packing boxes in "60 mìnutes" and

Elias will fold 210 packing boxes in "70 mìnutes".

8 0

3 years ago

The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f

Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen who carry a credit card balance.

The formula for the interval is:

p'₁± $Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }$

$Z_{1-\alpha /2}= Z_{0.95}= 1.648$

0.37±1.648* $\sqrt{\frac{0.37*0.63}{1000} }$

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂± $Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }$

0.48±1.648* $\sqrt{\frac{0.48*0.52}{1000} }$

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: $\sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015$

Seniors: $\sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016$

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0

3 years ago

If 36/5x=3/5 find x​

If 36/5x=3/5 find x