Answer:
Reversible chemical reaction favoring products.
Explanation:
Hello,
In this case, if we assume the following chemical reaction to be carried out:
We understand that it is under equilibrium conditions. In addition, based on the law of mass action, the present equilibrium constant is defined as:
Now, if Keq is greater than 1, it means that the concentration of the product B is greater than that of the reactant A, therefore, even though it is a reversible chemical reaction, it is favoring the formation of B it means the product(s).
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The grams of carbon monoxide that are needed to react is 148.68 grams
<u><em>calculation</em></u>
Step 1: find the moles of iron
moles =mass÷ molar mass
from periodic table the molar mass of Fe is 56 g/mol
= 198.5 g÷ 56 g/mol =3.54 moles
Step 2: use the mole ratio to determine the moles of carbon monoxide(Co)
that is from given equation Co : Fe is 3:2 therefore the moles of Co
= 3.54 x 3/2 = 5.31 moles
Step 3 : find mass of CO
mass = moles × molar mass
from periodic table the molar mass of Co = 12+16 = 28 g/mol
mass is therefore = 5.31 moles × 28 g/mol = 148.68 grams
Q = mCΔT
ΔT = 29.2 - 20 = 9.2 °C
Q = 120 x 4.184 x 9.2
Q = 4,619.1 Joules
The Standard Temperature and Pressure is 1 atm, 273 K
<u>Explanation:</u>
STP is Standard Temperature and Pressure
- Standard temperature is characterized as zero degrees Celsius (0°C), or 273.15 degrees Kelvin (273.15 K). This is the point of solidification of water at sea level, in the air at standard pressure.
Standard Temperature is
0° C in Celsius or 273 K in Kelvin
- Standard Pressure is 1 Atm, 101.3kPa or 760 mmHg or torr. STP is the "standard" condition regularly utilized for estimating gas density and volume.
Standard Pressure is
1 Atmosphere (atm)
760 Torricelli's (torr)
760 Millimeters of Mercury (mmHg)
101.325 KiloPascals (kPa)
Answer:
Explanation:
Hello!
In this case, for the undergoing chemical reaction at equilibrium:
Which means that pressure-based equilibrium constant is computed via the following equilibrium expression:
Thus, by plugging in the given pressures at equilibrium, the required Kp turns out:
Best regards!