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4 years ago

A symbiotic relationship in which both organisms benefit

Chemistry

2 answers:

LenaWriter [7]4 years ago

5 0

C hope that helps
Hahaha

Lana71 [14]4 years ago

5 0

The answer is B. Mutualism.

Parasitism is when one is benefiting while the other is being harmed; commensalism is when one is benefiting and the other isn’t affected; and mutualism is basically in its name, they’re both mutually benefiting.

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Choose a starting point in the water cycle and describe the process you would go through to move through the entire cycle.

Bogdan [553]

The water cycle describes how water evaporates from the surface of the earth, rises into the atmosphere, cools and condenses into rain or snow in clouds, and falls again to the surface as precipitation. ... The cycling of water in and out of the atmosphere is a significant aspect of the weather patterns on Earth.

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3 years ago

32 Points!!! Match the definition with correct keyword.

Temka [501]

Answer: Okay so here's the order lol from top to bottom

2, 1, 3, 4, 5

Explanation:

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3 years ago

Water will act as a Bronsted lowry acid with which of the following molecules?

Gekata [30.6K]

A. NH3
NH3 + H2O = NH+4 +OH-

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4 years ago

Read 2 more answers

3. Suppose a student determined the empirical formula of the compound to be K3[Fe(C2O4)3] 2H2O, rather than the correct formula

yuradex [85]

Answer:

Explanation:

When determining empirical formulas of hydrates we have to find the mass of water which left the hydrate when heating The sample. This amount of water calculated will provide us with the correct ratio of moles water / moles anhydrate since moles water > moles anhydrate. The mistake might have been done while determining the water that left the sample so then we see and impropre result in ratios.

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3 years ago

What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)

My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ → 2KCl + 3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1 .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

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4 years ago