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arlik [135]
3 years ago
12

Microwaves are used to heat food in microwave ovens. The microwave radiation is absorbed by moisture in the food. This absorptio

n heats the water, and as it becomes hot, so does the rest of the food. How many photons having a wavelength of 3.00 mm would have to be absorbed by 1.00 g of water to raise its temperature by 1.00∘C?
Chemistry
1 answer:
DanielleElmas [232]3 years ago
5 0

efw lol ewd sa dada

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Write a balanced half-reaction describing the oxidation of aqueous gold(i) cations to aqueous gold(iii) cations.
bezimeni [28]
<span>Balanced half-reaction: Au</span>⁺<span>(aq) </span>→ <span> Au</span>³⁺(aq) + 2e⁻.
Oxidation reaction is increasing of oxidation number of element, because element or ion lost electrons in chemical reaction.
Gold lost two electrons and change oxidation number from +1 to +3.
Reduction is lowering oxidation number because element gain electrons.
7 0
4 years ago
Once of the skills necessary for this experiment is dilution. If you have 1.95 mL of .806 M bleach, what will be the new concent
aleksley [76]

<u>Answer:</u> The concentration of diluted bleach solution is 0.0157 M

<u>Explanation:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated bleach solution

M_2\text{ and }V_2 are the molarity and volume of diluted bleach solution

We are given:

M_1=0.806M\\V_1=1.95mL\\M_2=?M\\V_2=100mL

Putting values in above equation, we get:

0.806\times 1.95=M_2\times 100\\\\M_2=\frac{0.806\times 1.95}{100}=0.0157M

Hence, the concentration of diluted bleach solution is 0.0157 M

6 0
3 years ago
Faunal succession and fossil correlation relate to the principle of superposition because there are fossils of certain organisms
yaroslaw [1]

Answer:

Alright love the answer would be true

6 0
3 years ago
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A thermometer having first-order dynamics with a time constant of 1 min is placed in a temperature bath at 100oF. After the ther
sveticcg [70]

Answer:

(a) See below

(b) 103.935 °F; 102.235 °F

Explanation:

The equation relating the temperature to time is

T = T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )

1. Calculate the thermometer readings after  0.5 min and 1 min

(a) After 0.5 min

\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-0.5/1} \right )\\ & = & 100 + 10\left (1 - e^{-0.5} \right )\\ & = & 100 + 10 (1 - 0.6065)\\ & = & 100 + 10(0.3935)\\ & = & 100 + 3.935\\ & = & 103.935\,^{\circ}F\\\end{array}

(b) After 1 min

\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-1/1} \right )\\ & = & 100 + 10\left (1 - e^{-1} \right )\\ & = & 100 + 10 (1 - 0.3679)\\ & = & 100 + 10(0.6321)\\ & = & 100 + 6.321\\ & = & 106.321\,^{\circ}F\\\end{array}

2. Calculate the thermometer reading after 2.0 min

T₀ =106.321 °F

ΔT = 100 - 106.321 °F = -6.321 °F

  t = t - 1, because the cooling starts 1 min late

\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-(t - 1)/\tau} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-(2 - 1)/1} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-1} \right )\\ & = & 106.321 - 6.321 (1 - 0.3679)\\ & = & 106.321 - 6.321 (0.6321)\\ & = & 106.321 - 3.996\\ & = & 102.325\,^{\circ}F\\\end{array}

3. Plot the temperature readings as a function of time.

The graphs are shown below.

6 0
3 years ago
Activation energy is ____. (1 point)
Usimov [2.4K]
Activation energy is defined as the least amount of energy that is needed to be available in a chemical system with potential reactants in order to result a chemical reaction. Therefore, the correct answer would be the first option: the heat released in a reaction. 
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3 years ago
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