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3 years ago

The mean of 6, 8, x + 2, 10, 2x - 1, and 2 is 9. Find the value of x and also the value of the observation in the data.

Mathematics

1 answer:

lapo4ka [179]3 years ago

8 0

Answer:

x = 9

Number of observations = 6

Sum of observations = 54

Step-by-step explanation:

Number of observations, n = 6

Mean = ΣX / n

(6 + 8 + x + 2 + 10 + 2x - 1 + 2) / 6 = 9

(27 + 3x) / 6 = 9

27 + 3x = 6 * 9

27 + 3x = 54

3x = 54 - 27

3x = 27

x = 27 / 3

x = 9

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The ration of child to teen to adult tickets sold at a water park on Saturday was 4:1:2. A total of 294 tickets were sold. How m

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Answer: 168 child tickets were sold.

Step-by-step explanation:

Given: The ratio of child to teen to adult tickets sold at a water park on Saturday was 4:1:2.

Let the number of child tickets = 4x , teen tickets = x , adult tickets = 2x

Total tickets = x+4x+2x = 7x =294

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3 years ago

ms.morgan bought 3.5 pounds of bananas at $0.51 a pound and 4.5 pounds of pineapple at $1.19 a pound.how much did she pay for th

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3 years ago

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Simplify: 12x3 - 3(2x3 + 4x -1) - 5x + 7

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Answer:

6x3 -17x + 10

The answer to this question would be 6x3 -17x + 10. Hope it helps!

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3 years ago

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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

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$x=\frac{-20(-)32} {8}=-6.5\ in$

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$(4+2x)=4+2(1.5)=7\ in$

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3 years ago

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Answer:

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