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valentinak56 [21]
2 years ago
14

Consider this Revenue Advertising Expense situation.

Mathematics
2 answers:
Dmitrij [34]2 years ago
7 0

Answer:

  • C. Package C: Php 32,000.00

Step-by-step explanation:

<u>Given function</u>

  • P = −50x³ + 2400x² − 2000, 0 ≤ x ≤ 32

x is the amount spent on advertising (in thousands of pesos).

Substitute x with 8, 16 and 32 and solve for P.

<u>The greatest value of P is at: </u>

  • x = 32 ( Php 32000.00)

and the value is

  • P = 817200.00

Another method is graphing.

See the attached picture for graphical solution.

Serhud [2]2 years ago
4 0

Answer:

Package C: Php 32,000.00

Step-by-step explanation:

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3 years ago
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

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155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0
3 years ago
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