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Anettt [7]
3 years ago
11

Help how do i solve for this ?

Mathematics
1 answer:
Tanya [424]3 years ago
3 0

Answer:

Solution:

Given,

Radius(r) = 11 ft

C = ?

Now,

c = 2\pi \: r

C = 2 × 3.14 × 11

= 70 cm

again,

C = 360°

angle = 315°

So,

C = 70 cm

or, 360° = 70 cm

or 1° = 70/360°

or 1° = 7/36

again ,

area = 7/36 × 315°

= 61.25 cm

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Nataly_w [17]

Answer:

D. 16

Step-by-step explanation:

GH^2 = GF \times GE

12^2 = 9 \times (9+x - 2)

144= 9 \times (7+x)

\frac{144}{9}= (7+x)

16= 7+x

16-7=x

9=x

GE = 9 + x - 2 = 9 + 9 - 2 = 18 - 2

GE = 16

4 0
3 years ago
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here a subtraction problem that has been solved incorrectly for 21-9=11 choose the addition sentence that check this subtraction
vitfil [10]

Answer:

21-9 = 12

Step-by-step explanation:

I don't know if this is the correct sentence you are looking for though but i hope it helps

6 0
3 years ago
How do you find the angle for n? If you can, please show work on how to get to the answer. Thank you!
PtichkaEL [24]
A triangle needs to add up to 180 degrees so 44 plus 37 is 81 so that last angle is 99 degrees then you do 180 minus that angle because those 2 angles need to equal up so not equals 81
5 0
3 years ago
A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
An airplane travel at a constant speed of 575 miles per hour.write and equation that can be used to determine the number of mile
Oxana [17]

Answer:

m = 575h

Step-by-step explanation:

Given

Rate = 575 miles/hour

Required

Determine the equation for the model

Represent the number of hours with h and the miles with m.

Using distance formula:

Distance = Speed * Time

In this case, it is:

Miles = Rate * Hour

So, we have:

m = 575 * h

m = 575h

3 0
3 years ago
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