The horizontal distance between light house and boat is 1588.78 feet approximately.
The figure is given by,
Here, AB = height of the lighthouse bacon light above the water = 139 feet
Now angle ACB = 5 degree
Let the horizontal distance of light house from the boat = BC = x feet
So by trigonometric function we get,
tan 5 = AB/BC
tan 5 = 139/x
x = 139/tan 5 = 1588.78 (approximately)
Hence the horizontal distance between light house and boat is 1588.78 feet approximately.
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Answer:
73.12 cm
Step-by-step explanation:
The perimeter of the square is 3 sides of the square (the 4th side is not included because of the semicircle)
P square = 3 s
=3 (16)
=48 cm
The perimeter of the semicircle is 1/2 of the circumference of a circle
P semicircle = 1/2 (pi *d)
=1/2 (pi* 16)
= 8 pi
= 8 (3.14)
=25.12 cm
The total perimeter is the sum of the square and the circle
P total = P square + P semicircle
=48+25.12
=73.12 cm