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3 years ago

Gary rode his bike for 5 hrs at 14 mph and then rode back at 35 mph how long did the trip take?

1 answer:

3 0

Answer = 7 Hours. Gary rode 14mph for 5 hours, on the way back he rode 35mph. 14 times 5 makes 70 and 35 times 2 makes 70, therefore it took Gary 7 hours total.

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to make 2 batches of nut nars, jayda needs to use 4 eggs how many eggs used in each batch of nut bars

muminat

To solve this problem, we need to set up a proportion.

2 batches of nut bars/ 4 eggs = 1 batch of nut bars / x eggs.

To solve this proportion, we use cross products, or multiplying the numerator of one number by the denominator of the other and setting them equal to one another.

(4 eggs) (1 batch) = (2 batches) (x eggs)

4= 2x

2=x

Therefore, 2 eggs are used in each batch of nut bars.

4 0

3 years ago

Integral of x"2+4/x"2+4x+3

dolphi86 [110]

I'm guessing you mean

$\displaystyle \int\frac{x^2+4}{x^2+4x+3}\,\mathrm dx$

First, compute the quotient:

$\displaystyle \frac{x^2+4}{x^2+4x+3} = 1 + \frac{4x-1}{x^2+4x+3}$

Split up the remainder term into partial fractions. Notice that

x ² + 4x + 3 = (x + 3) (x + 1)

Then

$\displaystyle \frac{4x-1}{x^2+4x+3} = \frac a{x+3} + \frac b{x+1} \\\\ \implies 4x - 1 = a(x+1) + b(x+3) = (a+b)x + a+3b \\\\ \implies a+b=4 \text{ and }a+3b = -1 \\\\ \implies a=\frac{13}2\text{ and }b=-\frac52$

So the integral becomes

$\displaystyle \int \left(1 + \frac{13}{2(x+3)} - \frac{5}{2(x+1)}\right) \,\mathrm dx = \boxed{x + \frac{13}2\ln|x+3| - \frac52 \ln|x+1| + C}$

We can simplify the result somewhat:

$\displaystyle x + \frac{13}2\ln|x+3| - \frac52 \ln|x+1| + C \\\\ = x + \frac12 \left(13\ln|x+3| - 5\ln|x+1|\right) + C \\\\ = x + \frac12 \left(\ln\left|(x+3)^{13}\right| - \ln\left|(x+1)^5\right|\right) + C \\\\ = x + \frac12 \ln\left|\frac{(x+3)^{13}}{(x+1)^5}\right| + C \\\\ = \boxed{x + \ln\sqrt{\left|\frac{(x+3)^{13}}{(x+1)^5}\right|} + C}$

3 0

2 years ago

Which of the following equations has a graph that passes through (3, 3) and has a slope of −2?

Tatiana [17]

Answer:

y - y1 = m(x - x1)

y - -3 = 3(x - 1)

y + 3 = 3x - 3

y = 3x - 3 - 3

y = 3x - 6

Step-by-step explanation:

Thie equation is in slope-intercept form (y = mx + b)

The y-intercept is -6 .... ((0, -6) is one point on the line.

It is given that (1, -3) is also on the line. So to graph, plot those

2 points and connect them with a line.

7 0

3 years ago

Read 2 more answers

A tiny but horrible alien is standing at the top of the Empire State Building (which is

Leto [7]

Answer:

87.7 degrees.

Step-by-step explanation:

In triangle ABC, attached.

The height of the building |AB|=443 meters

The distance of the agent across the street , |BC|=18 meters

We want to determine the angle at C.

Now,

$Tan C=\dfrac{|AB|}{|BC|} \\C=arctan (\dfrac{|AB|}{|BC|} )\\=arctan (\dfrac{443}{18} )\\=87.67^\circ\\\approx 87.7^\circ $(correct to the nearest tenth)$

The agent should sfoot his laser gun at an angle of 87.7 degrees.

7 0

3 years ago

Secants AC and DB intersect at point E inside the circle. Given that the measure of arc CD = 40o, arc AB = 60o, and arc BC = 160

s344n2d4d5 [400]

Answer:

C. $130^{\circ}$

Step-by-step explanation:

Please find the attachment.

We have been given that secants AC and DB intersect at point E inside the circle. Given that the measure of arc $CD = 40^o$ , arc $AB = 60^o$ , and arc $BC = 160^o$ . We are asked to find the measure of angle AED.

We know that the measure of angle formed by two intersecting secants is half the sum of measure of the arcs by intercepted by the angle and its vertical angle.

$\angle AED=\frac{\widehat{BC}+\widehat{AD}}{2}$