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3 years ago

Ayo i need help on math 3x-45=12

Mathematics

1 answer:

Leto [7]3 years ago

6 0

x=19

add 45 to both sides 3

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Find the measure of the indicated angle.

marusya05 [52]

Answer:

the answer is 96°

Step-by-step explanation:

it is an isosceles triangle as it's 2 sides are equal.

for an isosceles triangle, the angles made by the equal sides with the third side are equal.

and the sum of all angles in a triangle = 180°

42 + 42 + x = 180

x = 180 - 84

X = 96°

4 0

3 years ago

BRAINLIEST ANSWER PLZ HELP THANK YOU

insens350 [35]

For this you should just look at the y value in each ordered pair.

The first one should be no.

second one: yes

third one: no

fourth one: no

4 0

4 years ago

Read 2 more answers

Ok so i know that you want brainleist but pls answer first?!

andrew-mc [135]

Step-by-step explanation:

$Expression: \frac{40}{y - 16}$

$When \: y=20, \: the \: value \: of \: the \: expression \: is \: \frac{40}{4} = 10$

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3 years ago

If 300 cubes can fit in the rectangular prism below what is the edge length of each cube

ehidna [41]

The answer is 1/4 inches

7 0

3 years ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)

yan [13]

Answer:

P=1620

Third option

Step-by-step explanation:

Horizontal Asymptotes

A given function is said to have a horizontal asymptote in y=a, if:

$\displaystyle \lim _{x\rightarrow -\infty }f(x)=a$

Or,

$\displaystyle \lim _{x\rightarrow +\infty }f(x)=a$

For the given function, the population of the species of bird is given by :

$\displaystyle p(t)=\frac{1620}{1+1.15e^{-0.042t}}$

Where t is the time in years. To find the horizontal asymptote, we should compute both limits to check if they exist.

$\displaystyle \lim _{x\rightarrow +\infty }\frac{1620}{1+1.15e^{-0.042t}}=\frac{1620}{1+0}=1620$

When t tends to plus infinity, P tends to 1620 .

The second asymptote is computed by:

$\displaystyle \lim _{x\rightarrow -\infty }\frac{1620}{1+1.15e^{-0.042t}}=\frac{1620}{1+\infty}=0$

When t tends to minus infinity, P tends to zero. Since the domain of P is $t\geq 0$ , this asymptote is not valid, thus our only asymptote is

$\boxed{P=1620}$

6 0

3 years ago