120 has the same value as 12 tens
Line 3 is where the error begins. 12^2 is not equal to 24, it is equal to 144. Same for 18^2.
Answer:
468 = hypotenuse^2
Hypotenuse= square root of 468
<span>5x= 6x^2 -3
</span><span>6x^2 -5x -3
a = 6
b = -5
c = -3
x = [-b +- sq root(b^2 -4ac)] / 2a
x = [--5 +- </span><span>sq root (25 -(4*6*-3)] / 12
</span><span>x = [5 +- sq root (25 + 72)] / 12
x = [5 + sq root (97)] / 12
x = 5 +- </span><span>9.84886] / 12
x1 = </span><span><span><span>1.237405
</span>
</span>
</span>
<span>
x2 = </span><span><span><span>-0.404072
</span>
</span>
</span>
Put simply, you have to work backwards in making the equations. Start with the product of 8/3 and 9.
*9 Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
(
*9)*
, or dividing everything by 4.
(
*9)/4
Finally, subtract three.
The final equation would read:
((
*9)*
)-3Using PE(M/D)(A/S), we'd start with

*9
3 and 9 cancel out to be 1 and 3, leaving us with

, or 8, and 3 and this part of the equation reading 8*3, which is 24.
The next step is

, which is 6.
Lastly we subtract 3 from six, leaving us 3.
Answer:
Step-by-step explanation:
To start calculating, we first need to make some proof.
Firstly, since AB = AC, we know that ΔABC is isosceles, which means that ∠ABC = ∠ACB.
Now, looking only to ΔBDE and ΔCDF, we can see that they are similar, because the two of its angles are congruent:
∠BED=∠CFD
∠DBE=∠DCF
To make it easier to visualize which are the corresponding vertexes, we can draw them like this:
And we need to remember that BC is 24, so:
BD+CD=24
Since the triangles are similar, their corresponding sides have constant ratio, which we can calculate from the corresponding sides DE and CF:

This ratio is the same for the other corresponding sides, so we can apply that for BD and CD:

Thus, the measure of CF is approximately 13, alternative D.