Answer:
c . Two angles whose sum is 180°
Step-by-step explanation:
Hope it helps you in your learning process
Answer:
160,000 tins
Step-by-step explanation:
To find the number of tins, divide the fill rate by the volume per tin.
__
(2·(1000 L)/min)×(60 min)/(1 h)/(0.75 L/tin) = 160,000 tin/h
160,000 tins of paint can be filled in 1 hour.
_____
<em>Additional comment</em>
That's one tin every 22.5 milliseconds. It would be a feat of engineering to move that volume without splashing.
There are 60 minutes per hour. There are 1000 liters per cubic meter.
Answer: The p-value is 0.154.
Step-by-step explanation:
Since we have given that
We claim that
Null hypothesis :

Alternate hypothesis :

Population mean = 20 hours
Sample mean = 18.5 hours
Sample standard deviation = 4.3 hours
Sample size n = 35
So, test statistic would be

So, the p value would be 0.154.
Hence, the p-value is 0.154.
The general equation that represents the circle is x² + y² + 8x - 18y + 72 = 0
<h3>How to determine the circle equation?</h3>
The center of the circle is given as:
Center, (a,b) = (-4,9)
The diameter is given as:
d = 10
Calculate the radius (r)
r = 10/2 = 5
The circle equation is then calculated using:
(x - a)² + (y - b)² = r²
So, we have:
(x + 4)² + (y - 9)² = 5²
Expand
x² + 8x + 16 + y² - 18y + 81 = 25
Collect like terms
x² + y² + 8x - 18y + 16 + 81 - 25 = 0
Evaluate
x² + y² + 8x - 18y + 72 = 0
Hence, the general equation that represents the circle is x² + y² + 8x - 18y + 72 = 0
Read more about circle equations at:
brainly.com/question/1559324
Answer:

Step-by-step explanation:
We want to evaluate the limit:

To do so, we can divide everything by <em>x</em>². So:

Now, we can apply direct substitution:

Any constant value over infinity tends towards 0. Therefore:

Hence:

Alternatively, we can simply consider the biggest term of the numerator and the denominator. The term with the strongest influence in the numerator is 3<em>x</em>²<em>, </em>and in the denominator it is <em>x</em>². So:

Simplify:

The limit of a constant is simply the constant.
We acquire the same answer.